What is the slope-intercept form of 6x −2y−4 = 0?
Can you please explain with some details?

Answers

Answer 1
Answer: 6x -2y-4 = 0 \n \nthe \ slope \ intercept \ form \ is : \n \n y= mx +b \n \n6x -2y-4 = 0 \n \n-2y =-6x+4\ \ /:(-2)\n \ny=(-6)/(-2)x+(4)/((-2))\n \ny=3x-2 \n \n the \ slope \ (the multiplier \ of \ x \ represented \ by \ m ) \ is \3\n \n and \ the \ y-intercept \ (the constantrepresented \ by \ b \ ) \ is \ -2
Answer 2
Answer: the slope intercept form is y=mx+b
-2y=-6x+4
divide both sides by -2
y=3x-2

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Jamar has a bag that contains apple chews, lemon chews, and peach chews. He performs an experiment. Jamar randomly removes a chew from the bag, records the result, and returns the chew to the bag. Jamar performs the experiment 59 times. The results are shown below: An apple chew was selected 53 times. A lemon chew was selected 3 times. A peach chew was selected 3 times. Based on these results, express the probability that the next chew Jamar removes from the bag will be apple chew as a decimal to the nearest hundredth.​

Answers

Answer:

the answer is 0.90

Step-by-step explanation:

Answer:

The probability that the next chew Jamar removes from the bag will be an apple chew is:

P(apple) = number of times an apple chew was selected / total number of experiments

P(apple) = 53 / 59

P(apple) ≈ 0.90

Rounded to the nearest hundredth, the probability that the next chew Jamar removes from the bag will be an apple chew is 0.90.

Step-by-step explanation:

Which graph correctly solves the system of equations below?y = 2x2 − 3
y = −x2

one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1.

one quadratic graph opening up and one quadratic graph opening down. They intersect at 0, negative 3.

two quadratic graphs opening up. They intersect at 0, negative 3.

quadratic graph opening up and quadratic graph opening down. They intersect at 1, 2 and negative 1, 2

Answers

Answer:

one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1

i.e. they intersect at (1,-1) and (-1,-1)

Step-by-step explanation:

We are asked to find which graph correctly solves the system of quadratic equations:

y=2x^2-3

and y=-x^2

on solving the equation by the method of substitution i.e. on equating both the equations we get:

2x^2-3=-x^2\n\n2x^2+x^2=3\n\n3x^2=3\n\nx^2=1\n\nx=+1,x=-1

Now on putting the value of x in any of the equations we get the value of y as:

y=-1

Hence, the point of intersections of both the graph is:

(1,-1) and (-1,1).

Also the graph of the quadratic equation:

y=2x^2-3

opens upward.

and graph of the quadratic equation:

y=-x^2

opens downward.

Hello,

answer A is True, others are false


Calculate cos theta to two decimal places

Answers

Answer:

B. 0.72

Step-by-step explanation:

In order to find the answer we need to use the following formula:

a^2=b^2+c^2-2bc*cos(\theta) where:

a, b, c are the length of the sides and \theta the angle, so:

7^2=10^2+8^2-(2*10*8)*cos(\theta)

49=164-(160)*cos(\theta)

cos(\theta)=0.71875

In conclusion, cos(\theta)=0.72, so the answer is B.

1 Identify whether the series summation of 16 open parentheses 5 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.A This is a convergent geometric series. The sum cannot be found. (I think this)

B This is a divergent geometric series. The sum cannot be found.

C This is a convergent geometric series. The sum is –4.

D This is a divergent geometric series. The sum is –4.

Answers

sum to infinite for
1) arithmetic series is always divergent, sum is infinite.
2) geometric series is convergent if -1 < common ratio < 1 otherwise it is divergent.

b) is correct , (r = 5) > 1

What are the solutions to the equation x-7/x=6? a. x=-7 and x=1
b. x=-6 and x=-1
c. x=-1 and x=7
d. x=1 and x=6

Answers

x - (7)/(x) = 6
(x^(2))/(x) - (7)/(x) = 6
(x^(2) - 7)/(x) = 6
x^(2) - 7 = 6x
x^(2) - 6x - 7 = 0
x^(2) - 7x + x - 7 = 0
x(x) - x(7) + 1(x) - 1(7) = 0
x(x - 7) + 1(x - 7) = 0
(x + 1)(x - 7) = 0
x + 1 = 0    or    x - 7 = 0
x = -1    or    x = 7

Answer:

C


Step-by-step explanation:


The equation is x-(7)/(x)=6

LCM of the denominator on the left side gives us:

(x^(2)-7)/(x)=6

Cross multiplying and arranging gives us:

x^(2)-7=6x\nx^(2)-6x-7=0

This is a binomial, to factor this, we have to think of 2 numbers that multiplied gives us -7 [the constant term] and added gives us -6 [the coefficient of x].

The two numbers are: -7 and 1.

Now we can write:

x^(2)-6x-7=0\n(x-7)(x+1)=0

Hence, either (x-7)=0 OR (x+1)=0. This gives us two solutions, x=7 and x=-1. Answer choice C is correct.

Roderigo has just finished paying back his $8,575 unsubsidized Stafford loan, which he took out to fund his four-year degree. The loan had a duration of ten years and an interest rate of 7.1%, compounded monthly. Roderigo will allow interest capitalization. If Roderigo made monthly payments to pay off his loan, how much interest did he pay in total? Round all dollar values to the nearest cent.

Answers

Answer:

Roderigo will pay $7353.80 in interest.

Step-by-step explanation:

Interest capitalization means the interest earned is added to the principle amount so first we will use compound interest formula.

Compound interest formula is :

p(1+(r)/(n) )^(nt)

p = 8575

r = 7.1% or 0.071

n = 12

t = 4

Putting the values in formula we get;

8575(1+(0.071)/(12) )^(48)

Solving this we get;

Amount = $11381.94

For the next part we have EMI formula as:

(p* r*(1+r)^(n) )/((1+r)^(n)-1 )

p = 11381.94

r = 7.1/12/100=0.005917

n = 12*10=120

(11381.94*0.005917*(1+0.0059147)^(120) )/((1+0.005917)^(120)-1 )

= (11381.94*0.005917*(1.005917)^(120) )/((1.005917)^(120)-1 )

EMI = $132.74

Now total payments made in 120 months (10 years) = 132.74*120=15928.80 dollars

Now, interest paid = 15928.80-8575=7353.80 dollars

Hence, Roderigo will pay $7353.80 in interest.

___________C. $7,353.80