A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $135 for 100 minutes of usage and $375 for 500 minutes of usage. An equation can be written to show the relationship between the total minutes used (x) and the total monthly charges (y). Which of the following best describes the steps to draw the graph of y against x? Draw a graph which joins the points (135, 100) and (375, 500) and has a slope = 0.6 Draw a graph which joins the points (100, 135) and (500, 375) and has a slope = 0.6 Draw a graph which joins the points (100, 135) and (500, 375) and has a slope = 1.67 Draw a graph which joins the points (135, 100) and (375, 500) and has a slope = 1.67

Answers

Answer 1

Answer:

Answer:

The graph which describes the relationship between company charges and minutes of usage is the graph containing the points (100,135) and (500,375) and has a slope of 0.6. Where the first coordinate of the points are the minutes and the second coordinate the charges.

Step-by-step explanation:

As the first coordinate of a point always represents the x variable and the second coordinate they value, the possible options to describes this situation are:

The graph join which joins the points (100,135) and (500,375) and has a slope =0.6

The graph join which joins the points (100,135) and (500,375) and has a slope =1.6

The other options are not possible since the order of the coordinates is inverted.

One of the possibilities showing above must be rejected since one have the incorrect slope. To verify the correct slope we calculate the variation of y coordinates and divide by the variation of x coordinates:

$m=((y2-y1))/((x2-x1))$

Assuming the point named '2' as the point (100,135) and the point named '1' as (500,375):

$m=((375-135) \$)/((500-100) minutes)$

$m=((240) \$)/((400) minutes)$

$m=0.6 \$/minutes$

Thus, that the graph joining the points (100,135) and (500,375) and has a slope of 0.6 the only possible action.

Answer 2

Answer: The correct answer to this question is letter "B. Draw a graph which joins the points (100, 135) and (500, 375) and has a slope = 0.6." The one on the x axis should be the number of minutes and on the other hand, the one on the y axis should be the amount being charged.

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I don’t get this. Can any help me

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The average is the sum of the observations divided by the count.

So the sum of the observations is the count times the average.

So the 9 teachers together make 9(1000)=$9000 per week. The 20 staff (9 teachers + 11 aps) makes 20(1275)=25500.

So the 11 aps must make 25500-9000=16500

So the mean ap salary is 16500/11 =$1500 per week

Clearly management is where it's at.

Check: (1500*11+1000*9)/20 = 1275 good

Choice B

The answer is b. Or 1,500.

How do you solve this equation?

Answers

Thenswer is p is greater than or equal to 4. which, you already wrote.

steps:
1. subtract 140 from both sides. now you have: 15p (is greater than or equal to) 60.

2. divide both sides by 15.

3. simplify. now, the answer is p (is greater than or equal to) 4.

The inequation is:
140+15x≥200

15x≥200-140
15x≥60
x≥60/15
x≥4

Therefore: she has to sell at least 4 paintings

How do I find the perimeter of a triangle?

Answers

"Perimeter" is the distance all the way around it.

To find the perimeter of a triangle, collect these numbers:

-- length of one side
-- length of another side
-- length of the remaining side .

Add up those three numbers. Their sum is the perimeter of the triangle.

Perimeter is the distance around the object (in this case a triangle) and is found by adding up the length of each side

Look down for question

Answers

This has a lot of scary words and numbers in it, but it's all just fluff.
That big ugly formula is nothing but numbers, except for the 'h' in it
near the end. When you write your altitude in place of 'h' and push
all the numbers through your calculator, the answer is the air pressure
at that altitude.

All it's asking you to do is this:

-- Write ' 100 ' into the big formula.

-- Run all the numbers through the calculator and get the pressure at 100 meters.

-- Then write ' 1000 ' into the formula.

-- Run the whole thing through the calculator again, and see what
the pressure is at 1,000 meters.

-- Subtract, and see how much the pressure changed between 100 meters
and 1,000 meters.

You want to know what I think the whole idea is here ? I think the whole idea
is to get you to decide which things to do first as you calculate the formula,
AND to give you practice in using your calculator to do weird stuff.

In the formula, I see a power, a set of parentheses, two multiplications, and
one subtraction. You have to decide what order to do them in. And THEN,
you have to figure out how to do them all with your calculator.

Here's the order:

-- Inside the parentheses, multiply 2.25577x 10⁻⁵ by 'h' .
-- Inside the parentheses, subtract the result from ' 1 '.
-- Take the number inside the parentheses, and raise it to the 5.25588 power.
-- Then multiply the result by 101,325 .

For 100 meters altitude, the pressure you should get is 100,129 pascals.

Make sure you can get that with your calculator when you put '100' in place
of 'h'. And then, when THAT works, do it with 1,000 in place of 'h'.

The number you get for 1,000 meters should be about 10,254 pascals less.

What is the answer to the equation

Answers

4^-4

= 1 / ( 4*4*4*4)

= 1 / 4^4

= 1 / 256

= 0.0039

I hope that's help !

It is 1/256
I arroved at becaues i used one of the laws of exponents. If you have a Number with a negative exponent you just put it under one so the number becomes your denominator that's how I arrived at my answer.

Simplify each expression so that no negative exponents appear in the final result. Assume that all variables represent nonzero numbers.

Answers

$((2p)/(q^(2))) ^(3) ((3p^(4))/(q^(-4)))^(-1)$ Multiply the outside exponent into each

$((2p^(3))/(q^(6)) )((3p^(-4))/(q^(4)) )$ Multiply together

$(6p^(-1))/(q^(10)) = (1)/(q^(10)6p^(1))$

When you multiply an exponent DIRECTLY into another variable(with an exponent), you multiply the exponents.

For example:

(x²)³ = $x^(6)$

$(x^(4))^(5) = x^(20)$

When you multiply a variable with an exponent into another variable with an exponent, you add the exponents.

For example:

$(x^(2) )(x^(3) )=x^(5)$

$(x^(1) )(x^(3)) = x^(4)$

First I multiplied the outside exponents into the numerator and the denominator.

When you have a negative exponent, you move it onto the other side of the fraction to make it positive.

For example:

$x^(-2) = (1)/(x^(2))$

$(x)/(y^(-1)) = x(y^1)$

$(1)/(y^(-2)) = y^2$

Sorry if this is confusing

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