How long does water evaporation take? What factors influence it?

Answers

Answer 1
Answer: there is no certain time on how long it takes. Because the factors will always be different and the factors heavily affect the evaporation time. Some factors include: humidity, heat, how the sun is visible (whether clouds are covering it or not)
Answer 2
Answer: There is not any fix time for evaporation...every liquid has different boiling point....when any liquid boils completely then it start evaporating.

Six factors that influence evaporation are :-
(1) Wind assists evaporation
(2) Heat assists evaporation
(3) Increase in surface area exposed assists evaporation
(4) Dryness assists evaporation
(5) Rate of evaporation depends upon the nature of the liquid
(6) Vapor pressure

 







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Two aircraft leave an airfield at the same time. One travels due south at an average velocity of 85 m s 1and the second travels due east at an average velocity of 71 ms −1 . Calculate the distance between the planes after 6 hours. Give your answer in km, to the nearest km. km

Part 1. A girl leaves a history classroom and walks 10 meters north to a drinking fountain. Then she turns and walks 30 meters south to an art classroom. What is the girl's total distance traveled? Part 2. Using the information above from Part 1. What is the girl's total displacement from the history classroom to the art classroom?

Answers

The total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.

What will be the distance and displacement of the girl?

Distance = total amount of path followed by any body called distance.

Displacement= The minimum distance between two points irrespective to the path followed by the body is displacement.

It is given that

Distance traveled to north direction = 10 metres

Distance traveled to south direction= 30 metres

So the path followed by the girl in total = North direction + south direction

                                                                 = 10+30

                                                                 = 40 meters

And the displacement  = min distance between History class and fountain

                                      = 30 meters

total distance traveled by the girl will be 40 meters and the displacement will be 30 meters.

To learn more about Distance and Displacement follow

brainly.com/question/127432

She walks/travels 40 meters. Her displacement is 20 metres because she walked 10m, back those same 10m and the 20m to the art classroom.

Which of the following is an example of a decomposition reaction?a. photosynthesis
b. digestion
c. polymerization
d. exchange of ions between two compounds

Answers

The answer is (b) digestion.
A decomposition reaction is a process in which a single compound breaks into two or multiple elements or compounds. A best example is digestion where a large insoluble food molecules breakdowns into small water-soluble molecules so that they can be absorbed into the watery blood plasma.

A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at rest, how fast is it moving after it travels 3 meters?

Answers

The box has 3 forces acting on it:

• its own weight (magnitude w, pointing downward)

• the normal force of the incline on the box (mag. n, pointing upward perpendicular to the incline)

• friction (mag. f, opposing the box's slide down the incline and parallel to the incline)

Decompose each force into components acting parallel or perpendicular to the incline. (Consult the attached free body diagram.) The normal and friction forces are ready to be used, so that just leaves the weight. If we take the direction in which the box is sliding to be the positive parallel direction, then by Newton's second law, we have

• net parallel force:

F = -f + w sin(35°) = m a

• net perpendicular force:

F = n - w cos(35°) = 0

Solve the net perpendicular force equation for the normal force:

n = w cos(35°)

n = (15 kg) (9.8 m/s²) cos(35°)

n ≈ 120 N

Solve for the mag. of friction:

f = µn

f = 0.25 (120 N)

f ≈ 30 N

Solve the net parallel force equation for the acceleration:

-30 N + (15 kg) (9.8 m/s²) sin(35°) = (15 kg) a

a ≈ (54.3157 N) / (15 kg)

a ≈ 3.6 m/s²

Now solve for the block's speed v given that it starts at rest, with v₀ = 0, and slides down the incline a distance of ∆x = 3 m:

v² - v₀² = 2 ax

v² = 2 (3.6 m/s²) (3 m)

v = √(21.7263 m²/s²)

v ≈ 4.7 m/s

A train travels 225 kilometers in 2.5 hours. What is the train’s average speed?

Answers

the train travells at he speed of 225 km/2.5h
now
225km=225000m
2.5 hr=150min=9000s
=>avg sp of train is=225000/9000s=25m/s

Answer:

562.5

Explanation:

While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the speed of the tennis ball is km/h.

Answers

the answer is 11 km/h ... i just took the test

8 km/h I think good luck if it's wrong

A dock worker loading crates on a ship finds that a 24 kg crate, initially at rest on a horizontal surface, requires a 65 N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 50 N is required to keep it moving with a constant speed. The acceleration of gravity is 9.8 m/s 2 . Find the coefficient of static friction between crate and floor.

Answers

Answer:

0.276

Explanation: Here we have to consider the kinetic friction force acting on the body. If it is going at a constant speed according to newton's 1 st law. There was'not net force induced at the system. There for kinetic friction foce must be equal to the 50N .

But here we have been asked to get cofficient of static friction . There for you have to get static friction force. It should be 65N.

Mass of the object is 24. Then the reaction between surface and the object would be 24*9.8 = 235.2 N

There for using this,

Static friction force = Cofficient of static friction * Reaction

Cofficient of static friction = 65/235.2

= 0.276

Answer:

\mu_s=0.276

\mu_k=0.213

Explanation:

It is given that,

Mass of the crate, m = 24 kg

Force acting on the crate when it is at rest, F_r=65\ N

When the crate is in motion, force acting on the crate, F_m=55\ N

To find,

The coefficient of static friction between crate and floor

Solution,

When the crate is at rest, the force acting on the crate is given by :

F_r=\mu_sN

65=\mu_s* 24* 9.8

\mu_s=0.276

When the crate is in motion, the force acting on the crate is given by :

F_s=\mu_kN

50=\mu_k* 24* 9.8

\mu_k=0.213

Hence, this is the required solution.