Inertia is a property of an object that resists changes in motion, and its quantity is directly proportional to the object's mass. Therefore, a shopping cart full of groceries, having a greater mass, will exhibit more inertia than an empty shopping cart.
In physics, inertia refers to the tendency of an object to resist changes in its motion. The greater an object's mass, the greater its inertia, making it harder to start or stop its movement. In comparing a shopping cart full of groceries and an empty one, the cart full of groceries will have a higher mass, thus a greater inertia.
Consider an experiment where you exert the same amount of force on both carts. The full cart would be more resistant to change in motion and would move slower or a shorter distance than the empty one due to the higher inertia it possesses.
The same principle can be applied to a group of students using two carts (A and B) for a one-dimensional collision experiment. Cart B with unknown mass is initially at rest while cart A with known mass moves towards it. Since mass directly influences inertia, if cart B was loaded with materials (like a shopping cart full of groceries), it would be harder to shift its motion than if it were empty.
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B) erosion
C) volcano
D) landslide
To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.
To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:
2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg
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To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.
The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.
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