Given:
mass is 3.1 kilograms
The acceleration due to gravity is 9.8m/s2
Required:
Weight
Solution:
W = mg
W = (3.1 kilograms)( 9.8m/s2)
W = 30.38 Newtons
Answer:
The force of the collisions creates pressure on the container. ... Explain why atmospheric pressure changes as depth changes. Atmospheric pressure increases as depth increases because at lower levels of the atmosphere, there is more air above that is being pulled down by gravitational force.
Explanation:
A golfer hits a 45 g golf ball during 2.0 × 10⁻³ s causing its final speed to be 38 m/s. The impulse of the golf ball is 1.7 kg.m/s. The average force that the club exerts on the golf ball is 850 N and the average force that the golf ball exerts on the club is -850 N.
A golfer hits a 45 g (m) golf ball resting on a tee so that the golf ball leaves the tee at the horizontal speed of 38 m/s (v). To answer the questions, we need to consider the concepts of impulse and linear momentum.
Impulse (I) equals the average net external force (F) multiplied by the time (t).
I = F × t [1]
Linear momentum (p) is defined as the product of a system's mass (m) multiplied by its velocity (v).
p = m × v [2]
The impulse experienced by the object equals the change in the linear momentum of the object.
I = F × t = m × Δv [3]
We will use the equation [3], considering that Δv = v because it starts from the rest.
I = m × v = 0.045 kg × 38 m/s = 1.7 kg.m/s
The club and the golf ball are in contact for 2.0 × 10⁻³ s (t). We will calculate the average force that the club exerts on the golf ball (Fcg) using the equation [1].
I = Fcg × t
Fcg = I / t = (1.7 kg.m/s)/(2.0 × 10⁻³ s) = 850 N
According to Newton's third law of motion, action and reaction have the same value and opposite signs. Thus, the average force that the golf ball exerts on the club (Fgc) is -850 N.
A golfer hits a 45 g golf ball during 2.0 × 10⁻³ s causing its final speed to be 38 m/s. The impulse of the golf ball is 1.7 kg.m/s. The average force that the club exerts on the golf ball is 850 N and the average force that the golf ball exerts on the club is -850 N.
Learn more about impulse here: brainly.com/question/904448
Answer:
Correct answer: (1) I = 1.71 kg m/s, (2) F = 855 N
Explanation:
Given:
The mass of the ball m = 45 g = 45 · 10⁻³ kg
Initial velocity V = 38 m/s
Contact time t = 2 · 10⁻³ s
(1) I = ?
The impulse is calculated according to the formula:
I = m · V = 45 · 10⁻³ · 38 = 1,710 · 10⁻³ = 1.71 kg m/s
I = 1.71 kg m/s
(2) F = ?
The average force is calculated according to the formula:
F = ΔI / Δt = 1.71 / (2 · 10⁻³) = 855 N
F = ΔI / Δt = 1.71 / (2 · 10⁻³) = 855 N
F = 855 N
God is with you!!!
Which is likely to occur in these areas?
A.
clear skies
B.
precipitation
C.
heat and humidity
D.
high winds
please help
The wave changes direction as it changes its speed. _______
The wave changes direction at an angle equal to the angle of incidence. ________
diffraction
reflection
refraction
PLEASE HELP!!
Answer:
Here is the answer.
Explanation:
The answers are:
1. Diffraction
2. Refraction
3. Reflection
Hope this helps!
Answer:
1 . rays should passs through correct center or points(i.e. optic center or focus)
2.your line representing rays should be straight and u should tell the nature of image
Explanation: