Answer: the canola oil.
Explanation:
According to the melting points reported, at 5°C canola oil, whose melting point is 10°C, will freeze (become solid), while the other three, corn oil, sunflower oil, and peanut oil, having melting points several degrees below 5°C, will remain in liquid state.
Therefore, by decantation or filtration, which are processes that permit separate solids from liquids in a mixture, you can separate easily the solid canola oil from the other three liquid oils.
After separating the canola oil, If you continue cooling the mixture and reach a temperature of - 5°C. the peanut oil, whose melting point is -2°C, whill freeze and you will be able to separate it (again by decantation or filtration).
The same operation, cooling a third time until a temperature around 12°C, will permit you to separate the remaining two oils.
As you see, the knowledge of the physical properties of the substances is a useful tool to separate mixtures.
Answer: The volume of liquid used will be 18.055 mL.
Explanation:
To calculate the volume of liquid, we use the equation for density which is:
We are given:
Mass of the liquid = 26 g
Density of the liquid = 1.44 g/mL
Volume of the liquid = ? mL
Putting values in above equation, we get:
Hence, the volume of liquid used will be 18.055 mL.
Answer : The net ionic equation will be,
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
(2) 2 electrons in the first shell
(3) 3 electron shells
(4) 22 neutrons