(3) (the potential energy of the products) – (the potential energy of the reactants)
(4) (the potential energy of the reactants) – (the potential energy of the products)
Answer:
B. CH3COOH + H2O CH3COO- + H3O+
Explanation: hope this helped :)
b. fulcrum
c. mechanical advantage
d. resistance force
Answer:
Mechanical Advantage
Explanation:
b. Carbon, atomic number 6
c. Neon, atomic number 10
d. Fluorine, atomic number 9
Answer:
Neon, atomic number 10, is stable.
Explanation:
Valencia electrons are the electrons found in the last electronic layer (called valence orbitals). These electrons are what determine the ability of the atom to form bonds. When an element joins another, it does so through its valence electrons.
The noble gases include the elements of group 18 of the periodic table. The noble gases are characterized by their very low chemical reactivity because they are very stable. This is because they have the full valence layer (complying with the octet rule, that is, they have 8 electrons at their last energy level, with the exception of helium that has 2 electrons), causing them to have a low tendency to capture or release electrons . That is why they are also called inert gases.
The Neon, whose atomic number is 10, belongs to the group of noble gases. So this element is stable.
Radical chlorination of pentane and neopentane results in different yields of the desired products due to the selectivity of the reaction. With neopentane, the reaction is very selective, producing a higher yield of neopentyl chloride, while with pentane, the reaction isn't selective, leading to various isomers and a lower yield of 1-chloropentane.
Radical chlorination of pentane isn't an efficient method to prepare 1-chloropentane because it doesn't give a high yield of the desired product. This is due to it being a non-selective process, leading to the formation of several isomeric products. In the case of pentane, several different hydrogens can be replaced creating many possible isomers of chloropentane.
On the other hand, radical chlorination of neopentane or (CH3)4C is a good way to prepare neopentyl chloride or (CH3)3CCH2Cl. This is because neopentane has a far greater proportion of equivalent tertiary hydrogens. When chlorination occurs, it's most likely to happen at these sites, producing a higher yield of the desired neopentyl chloride product with less chance of isomer formation.
This difference is due to the selectivity and specificity of the radical chlorination reaction on neopentane versus pentane. Radical chlorination is not very selective with pentane but is quite selective with neopentane due to the type of hydrogens present, thus making it a more ideal reaction.
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