Answer:
aka: A
Explanation:
The equilibrium constant Kc for the given reaction is calculated as [Fe3+]/[Ag+][ Fe2+] = 1.76, which is not among the provided answer choices.
To calculate the equilibrium constant, Kc, for the reaction Ag + (aq) + Fe2+ (aq) <==> Ag(s) + Fe3+ (aq), you need to know the concentrations of the ions at equilibrium. According to the question, the concentration of Ag+ is 0.44 mol/1.00 dm^3. Because AgNO3 completely dissociates into Ag+ and NO3- ions, the initial concentration of Fe2+ would also be 1.00 mol/dm^3. Given that the reaction has gone to completion, the concentration of Fe2+ at equilibrium would be 0.56 mol/dm^3 (1.00 - 0.44).
Furthermore, the reaction creates an equivalent amount of Fe3+, so its concentration at equilibrium would also be 0.44 mol/dm^3. Therefore, the equilibrium constant, Kc, is calculated as [Fe3+]/[Ag+][ Fe2+] = (0.44)/(0.44 * 0.56) = 1.76. Looking at the answer choices given, none of them matches with the calculated value. So, the correct value might be an option not mentioned here.
#SPJ3
(2) atomic number
(3) first ionization energy
(4) selected oxidation state
Answer: Step 1: List the known quantities and plan the problem. Known. 4.96 moles O2; 1 mol = 22.4
Explanation: I hope that helped.
Answer:
D
Explanation:
Answer:
T = 291 K
Explanation: