There are 376 stones in three piles. The second pile has 24 more stones than the first. The third pile has twice as many stones as the second. How many stones in each pile?

Answers

Answer 1

Answer: Let the stones of each piles be x, y and z respectively.

thus, x + y + z = 376

x=x
y = x + 24
z= 2y = 2(x+24)

This becomes x + x + 24 + 2(x+24) = 376

= 4x + 24 + 48 = 376

= 4x + 72 = 376

Thus, 4x = 304

Thus, x = 76

and y = 76 + 24 = 100

and z = 2 x 100 = 200

Thus, first pile has 76 stones, second pile has 100 stones and third pile has 200 stones

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What is equevelent to 15/12

Answers

Answer:

5/4, 10/8, 15/12, 20/16, 25/20, 30/24, 35/28, 40/32, 45/36, 50/40, 55/44, 60/48, 65/52, 70/56, 75/60, 80/64, 85/68, 90/72, 95/76, 100/80

Step-by-step explanation:

all of those numbers are equivalent to 15/12

5/4 , 15/12 , 90/72 and more

The following function represents the value of a house, in dollars, after x years:f(x) = 242,000(1.04)x

What does 242,000 represent?

The present value of the house
The value of the house after x years
The increase in the value of the house each year
The increase in the value of the house after x years

Answers

Answer: The present value of the house

Step-by-step explanation:

Given: The following function represents the value of a house, in dollars, after x years:

$f(x) = 242,000(1.04)^x$

When we substitute x=0 in the above equation, we get

$f(0)=242,000(1.04)^0=242,000(1)=242,000$

Since at x=0, the function represent the initial value of a function.

Therefore, 242,000 represents the value of house in 0 years i.e. it represents the present value of the house.

A. The present value of the house

What is the value of 5/z when z=2

Answers

z=
2
−6−
56

=−3−
14

=−6.742

Z = 2

5/(2) = 2.5 or 5/2

Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(-1, 1) and Q(5,9)

Answers

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$((x_1+x_2)/(2), (y_1+y_2)/(2))$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \nx_1=-1 \n y_1=1 \n \n Q(5,9) \n x_2=5 \n y_2=9 \n \n(x_1+x_2)/(2)=(-1+5)/(2)=(4)/(2)=2 \n (y_1+y_2)/(2)=(1+9)/(2)=(10)/(2)=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=√((x_2-x_1)^2+(y_2-y_1)^2)$

$(-1,1) \n x_1=-1 \n y_1=1 \n \n (2,5) \n x_2=2 \n y_2=5 \n \n d=√((2-(-1))^2+(5-1)^2)=√(3^2+4^2)=√(9+16)=√(25)=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \n\boxed{(x-2)^2+(y-5)^2=25}$

How many solutions exist for the given equation?

1/2
(x + 12) = 4x – 1

Answers

There are two ways to look at this, one is by solving this and the other is by looking at the variable

First, if we want to solve it, we would take our equation, (i like decimals) .5(x+12)=4x-1 and distribute the .5 to both things in the parentheses. when we do that we get .5x+6=4x-1. now we get our variables to the same side by subtracting .5x from both sides. When we do this, we are left with 6=3.5x-1. next we add 1 to each side and get 7=3.5x. Now we divide each side by 3.5, and get x=2. Now we have to plug it into the original equation and get .5(2+12)=4(2)-1. when we simplify this we get .5(14)=7, which goes to 7=7. this is a true statement, so we know that x=2. since we only have one value for x, we know the answer is that only one solution exists.

Another way that is simpler, but not always accurate, is to look at the variable. There can only be as many solutions for x as the highest exponent x is to, in this case, x has no exponent so there can't be more than one solution, so we say that it has one solution. This way is a lot faster, but can be wrong if the equation has a false solution. This false solution happens when you solve the equation and get a value, but it doesn't work for the original equation.

The second way is a lot faster, but the first way will always give you the right answer

Answer:

One solution, option B for edge2020

Step-by-step explanation:

Which of the following equations are equivalent to-2m-5m-8 #-(-7) + m?D-15m-4md:7m-8-rn-4□-3m-8-4-m□m-4.7m-8-8.7m- 4-m□-8.3m-4-m

Answers

-2m - 5m - 8 = 3 + (-7) + m
-7m - 8 = 3 - 7 + m
-7m - 8 = m - 4 <=== here is one

m - 4 = -7m - 8 <=== another one
-8 - 7m = -4 + m <== and another one

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