For a trapezoid with a height of 7 centimeters and base lengths of 6 centimeters and 10 centimeters, the area is

Answers

Answer 1

Answer:

$\bf \textit{area of a trapezoid}\n\n A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\n h=height\n[-0.5em] \hrulefill\n a=6\n b=10\n h=7 \end{cases}\implies A=\cfrac{7(6+10)}{2} \n\n\n A=\cfrac{7(16)}{2}\implies A=7(8)\implies A=56$

Answer 2

Answer:

Answer:

Step-by-step explanation:

$A=(1)/(2) (b1+b2)h\n$

$A=(1)/(2) (6+10)7$

$A=(1)/(2) (16)7$

$A=8*7$

$A=56$

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Which of the following creates 90° angles at the points of intersection and also cuts a segment into two congruent pieces?A. Perpendicular line

B. Perpendicular bisector

C. Angle bisector

D. Bisector

Answers

Perpendicular bisector

There are white, red and blue cars in a parking lot. The number of each colour car is a factor of 36. There are twice as many white cars as red cars. The number of blue cars is twice that of black cars. The number of black cars is the product of two different prime numbers. The number of red cars is a square number that is not a multiple of 2. If there are 45 cars in the parking lot, calculate how many cars of each colour there are.

Answers

Black = 2*3 = 6 cars;
Blue = 2*2*3 = 12 cars;
Red = $3^(2)$ cars;
White = 2*9 = 18 cars;
The number of each colour car is a factor of 36( blue, red, white);
black + blue + red + white = 45 cars.

Answer:

45 cars.

Step-by-step explanation:

For black, 2*3=6 cars.

For blue, 2*2*3=12 cars.

For red 3 to the power of 2= 6 cars;

For white, 2*9=18 cars;

The number of each color would be a factor of 36. This means that all the cars being added equals 42.

(-1,2) and (-4,8)Find the slope of the line that contains the point
1. 2
2. 6/5
3. -2
4. -6/5