Answer:
C.
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Algebra I
Algebra II
Step-by-step explanation:
Step 1: Define
x² - 5x + 7 = 0
Step 2: Identify Variables
a = 1
b = -5
c = 7
Step 3: Find solutions
The solutions to the equation x² - 5x + 7 = 0 are:
x = (5 + i√3) / 2 or x = (5 - i√3) / 2
Option C is the correct answer.
We have,
To find the solutions of the quadraticequation x² - 5x + 7 = 0, we can use the quadraticformula:
x = (-b ± √(b² - 4ac)) / (2a)
For the given equation, the coefficients are:
a = 1
b = -5
c = 7
Substituting these values into the quadraticformula,
x = (-(-5) ± √((-5)² - 4(1)(7))) / (2(1))
Simplifying further:
x = (5 ± √(25 - 28)) / 2
x = (5 ± √(-3)) / 2
Since the discriminant (the value inside the square root) is negative, √(-3) is imaginary, meaning there are norealsolutions to this quadratic equation.
The solutions exist in the complex number system.
So,
√-1 = i
x = (5 ± i√3) / 2
This can be written as,
x = (5 + i√3) / 2
and
x = (5 - i√3) / 2
Thus,
The solutions to the equation x² - 5x + 7 = 0 are:
x = (5 + i√3) / 2 or x = (5 - i√3) / 2
Learn more about solutionsofequations here:
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2, 4/3, 8/9, 16/27
a. 7x-14x^4 +19x^3 +26x^5-18
Standard form:
degree:
name based on degree:
Answer:
Sure, I'd be happy to help!
The polynomial you provided is:
7x - 14x^4 + 19x^3 + 26x^5 - 18
To put this polynomial in standard form, we need to factor it. Here's the factored form of the polynomial:
7x(1 - 14x^3 + 19x^2 + 26x^4) - 18
Now, we can see that the degree of the polynomial is 4, so it is a quartic polynomial.
Based on the degree of the polynomial, we can classify it as a quartic polynomial.
Step-by-step explanation: