By using the relation between period and frequency, we conclude that the period of the fork is0.0023 seconds.
We know that the relation between period and frequency is:
T = 1/f
where T is the period and f is the frequency.
In this case, we know that the frequency of the fork is 440 Hz, where:
1 Hz = 1/s
Then the period of the fork will be:
T = 1/(440 Hz) = (1/440) s = 0.0023 s
Meaning that each complete vibration of the fork takes 0.0023 seconds.
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