MATHEMATICS HIGH SCHOOL

Factor this trinomial completely.15x²+11x-12
OA. (3x+3)(5x-4)
OB. (3x+4)(5x-3)
C. (x+3)(15x-4)
OD. (x+4)(15x-3)

Answers

Answer 1
Answer:

Answer:

B

Step-by-step explanation:

given the trinomial

15x² + 11x - 12

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 15 × - 12 = - 180 and sum = + 11

the factors are + 20 and - 9 , since

+ 20 × - 9 = - 180 and + 20 - 9 = + 11

use these factors to split the x- term

15x² + 20x - 9x - 12 ( factor the first/second and third/fourth terms )

= 5x(3x + 4) - 3(3x + 4) ← factor out (3x + 4) from each term

= (3x + 4)(5x - 3)

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Explanation:

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This is ur problem sis u got thisWhich of the following is equivalent to 16a2 – 49
A. (4a – 7) (4a – 7)
B. (4a + 7) (4a – 7)
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Answers

B. is your correct answer.

Find the midpoint of a line segment with the given endpoints.(8,-3) (-8,1)

Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

12

Step-by-step explanation:

Sam and Jeremy have ages that are consecutive odd integers.The product of their ages is 783. Which equation could be used to
find Jeremy’s age, j, if he is the younger man?
(1) j^2 + 2 = 783 (3) j^2 + 2j = 783
(2) j^2 - 2 = 783 (4) j^2 - 2j = 783

Answers

j, j+2 - consecutive odd integers
j - Jeremy's age
j+2 - Sam's age
The product of their ages is 783.

j(j+2)=783 \nj^2+2j=783

The answer is (3).
consecutive odd integers are 2 awya from each other
1,3,5,7,9...
since jeremy iis younger, he is 2 less than sam
j
s=j+2

sj=783
in terms of j
(j+2)j=783
distribute
j^2+2j=783

the answe ris the 3rd equation
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