Answer:
24 hours
Explanation:
b.) hydrogen
c.) gold
d.) table salt
a battery
B.
a generator
C.
mechanical energy
D.
electromagnetic energy
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@Akin
@AL2006
Answer:
C. Mechanical Energy
Explanation:
Took the test
Answer:
4.1. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. In other words, when one object exerts a force on another object, the second object exerts an equal force in the opposite direction on the first object.
4.2. Here's a labeled free-body diagram for Block A:
```
T (tension in the string)
↑
│
│
│
│
│
F (applied force)
──→ (direction of motion)
```
In this diagram, "T" represents the tension in the string, and "F" represents the applied force at an angle of 30° to the horizontal. The arrow indicates the direction of motion.
4.3. To find the frictional force acting on block A as it accelerates, we can use Newton's Second Law:
\[F_{\text{net, A}} = m_A \cdot a\]
Where:
- \(F_{\text{net, A}}\) is the net force acting on block A.
- \(m_A\) is the mass of block A (given as 15 kg).
- \(a\) is the acceleration (given as 2.08 m/s²).
Rearranging the equation to solve for \(F_{\text{net, A}}\):
\[F_{\text{net, A}} = 15 kg \cdot 2.08 m/s² = 31.2 N\]
Now, we need to consider the frictional force, which opposes the motion and acts in the direction opposite to the applied force. So, the frictional force is 31.2 N in the opposite direction of motion, making it:
Frictional force on block A = -31.2 N
However, since you want it in magnitude, it's 31.2 N.
4.4. To calculate the mass of block B, we can use the fact that block A and block B are connected by a string, so they experience the same acceleration. Therefore, we can use the following equation:
\[F_{\text{net, B}} = m_B \cdot a\]
Where:
- \(F_{\text{net, B}}\) is the net force acting on block B, which is the tension in the string.
- \(m_B\) is the mass of block B (unknown).
- \(a\) is the acceleration (given as 2.08 m/s²).
We already calculated that the tension in the string is 31.2 N. Plugging in the values:
\[31.2 N = m_B \cdot 2.08 m/s²\]
Now, solving for \(m_B\):
\[m_B = \frac{31.2 N}{2.08 m/s²} \approx 15 kg\]
So, the mass of block B is approximately 15 kg.
2. They both need to gain one electron.
3. Sodium needs to lose one electron, and chlorine needs to gain one electron.
4. Sodium needs to gain one electron, and chlorine needs to lose one electron.
Answer: The correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".
Explanation :
The electronic configuration of sodium (Na) is . It has only one vacant electron.
While the electronic configuration of chlorine is . It has seven valance electrons.
When Na reacts with Cl, Na will lose one electron and this lost electron gets transferred to chlorine. This forms a strong ionic bond.
So, the correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".