An individual with true self knowledge is familiar with

Answers

Answer 1
Answer: The best answer for this would be strength and weaknesses. An individual with true self knowledge is familiar with his or her strength and weaknesses. Once an individual know which is his weakness or strength, he or she will be able to decide through which he or she truly desires.
Answer 2
Answer:

In short @Taskmasters is correct But is is A. For plato


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Make the following conversion.
24.7 mL = _____ cm3
247
2470
2.47
24.7

Answers

since 1ml = 1 cm cubed its gonna be 24.7

24.7.....................................

you lift a 30 N crate 2 meters onto a shelf. it takes you 5 seconds to accomplish this. how much gravitional potential energy does the crate gain

Answers

Gravitational potential energy is equal to force times height. That's 30 x 2 = 60 Joules. It makes no difference how fast or how slow you do the lift.

the atomic mass of potassium is 39. if its atomic number is 9, it has how many neutrons within each potassium atom?

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Atomic number is actually 19 as it has 19 protons. To make up the mass number of 39 it needs 20 more nucleons, these must come in the form of neutrons so it has 20 neutrons.

a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at the bottom is 15 m/s. what is the lenght of the incline? how long does it take him to reach the bottom?

Answers

... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s

When the engineer first sees the car, the locomotive is 100m from the crossing and its speed is 30m/s. If the engineer reaction time is 0.47 s what should the magnitude of the minimum deceleration to avoid an accident?

Answers

Answer:

The deceleration must have the engineer to avoid the accident is

a=-5.238 (m)/(s^(2) )

Explanation:

x_(0)=100m\nv_(0)=30 (m)/(s) \nt=0.47 s

While the engineer reacts the train continue moving so

x_(f) = v*t= 30(m)/(s) *0.47s= 14.1 m

x_(t)=  x_(o)+x_(f)\nx_(t)=  100m-14.1m=85.9m

Now the final velocity have to be zero so using equation can find deceleration

V_(f) ^(2) =V_(o) ^(2)+2*a*x_(f)\n  0= V_(o) ^(2)+2*a*x_(f)\na=-(V_(o) )/(2*x_(f))\na=-((30(m)/(s)) ^(2) )/(2*85.9m) \na=-5.238 (m )/(s^(2) ) } \n

Make a island with all renewable energy soursws and how it works and about it but at year 9 level​

Answers

Answer:

How are we expected to make an island