Answer:
y = x + 1
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given line Q with equation
y = x - 5 ← in slope- intercept form
with slope m =
• Parallel lines have equal slopes , then
y = x + c ← is the partial equation of line R
to find c , substitute the point (6, 2 ) for x and y into the partial equation
2 = (6) + c = 1 + c ( subtract 1 from both sides )
1 = c
y = x + 1 ← equation of line R
b.153
c.154
d.155
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
Number of games she bowl = 4
Score of her in first three games are
149, 162, 152.
Her average score = 154
Let the score in her fourth game be 'x'.
As we know the formula for "Average ":
Hence, Her score in fourth game is 153.
Therefore, Option 'B' is correct.
(14x3y2z)4
The result of raising the polynomial (14x3y2z) to the 4th power is 38416x12y8z4. This is calculated by individually multiplying each part of the polynomial by itself 4 times.
The problem is asking you to calculate the result of raising a polynomial (14x3y2z) to the 4th power.
The operation refers to using the rule of powers which states that any base with an exponent is multiplied by itself the amount of times indicated by the exponent. The result should therefore be calculated as follows:
(14x3y2z)4 = 38416x12y8z4
To find the answer, we raised each part of the polynomial to the 4th power. 144 equals 38416, (x3)4 results in x12 because you multiply the exponents, (y2)4 results in y8 for the same reason and z4 because anything to the power of 4 is itself raised 4 times.
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The perpendicular are B) ||u+v|| = sqrt ||u||^2 + ||v||^2 and D) ||u+v|| less than ||u||+||v||
We have given that,
The relationships hold true for the sum of the magnitudes of vectors u and v,
We have determined which are perpendicular.
The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.
B) ||u+v|| = sqrt ||u||^2 + ||v||^2
AND
D) ||u+v|| less than ||u||+||v||
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it is
B) ||u+v|| = sqrt ||u||2 + ||v||2
AND
D) ||u+v|| less than ||u||+||v||
Answer:
Step-by-step explanation:
We have been given a function:
We will compare it with the genral equation which is:
Where, a is amplitude and period of function is
In given equation a is -3 and b is 4
So, period of the given equation is:
Yo can look at the graph in the attachment.
The a is the amplitude and the period of the function is
We have been given a function
We will compare it with the general equation which is
Where a is amplitude and period of the function is
In the given equation a is -3 and b is 4
So, the period of the given equation is:
You can look at the graph.
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