Enzo is making a scale drawing of the rectangle below.A rectangle has a length of 8 centimeters and width of 5 centimeters.

Enzo says that he can draw an enlarged rectangle that is 16 centimeters by 13 centimeters. Which explains whether Enzo is correct?

Answers

Answer 1
Answer:

Answer:

Enzo is not correct because he did not multiply the length and width by the same factor.

I do not think Enzo is not correct because he did not multiply the length and width by the same factor.

he is making a  drawing of the rectangle below.

A rectangle has a length of 8 centimeters and width of 5 centimeters.

Suppose a new rectangle will have the length of 16 cm.  

Enzo says that he can draw an enlarged rectangle that is 16 centimeters by 13 centimeters. Enzo is not correct because he did not multiply the length and width by the same factor.

Answer 2
Answer:

Answer:

Enzo is not correct because he did not multiply the length and width by the same factor.

Step-by-step explanation:


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Write a story problem in which you would have to multiply 5 × (-1/3) to find the answer.
At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m. Find the exact area of the larger circleFind the exact area of the smaller circle.Write an expression to find the exact area of the sidewalk (shaded portion).Find the approximate area of the sidewalk. Use 3.14 to approximate π. Answer:Find the exact area of the larger circle. Show your work. (1 point)A= N x 11 2 A = n? Find the exact area of the smaller circle. Show your work. (1 point)A= n 9 2 A=n?Write an expression to find the exact area of the sidewalk (shaded portion). Show your work. (2 points) 11 2 – 9 2 x nFind the approximate area of the sidewalk. Use 3.14 to approximate π. Show your work. (1 point) 11 2 x 3.14 – 9 2 x 3.14=
Find the value of x in the figure below and give the reason.

Reduce to lowest terms

Answers

Answer:

4 ft 5 in

Step-by-step explanation:

Adding:

   2\ ft\ 8\ in

+ 1\ ft\ 9\ in

We get 3\ ft\ and\ 17\ in.

17\ in can be further converted to ft\ and\ in

As 12\ in = 1\ ft

17\ in =12\ in + 5\ in=1\ ft + 5\ in

∴ Reduced form is =  3\ ft\ +1\ ft + 5\ in=4\ ft\ 5\ in

-3(x + 4) = (-x - 1)

Answers

Answer:

x=-5.5

Step-by-step explanation:

-3(x+4)=(-x-1)

1. Distribute

-3x+(-12)=-x-1

2. Simplify

-3x-12=-x-1

-2x-12=-1

-2x=11

x=-11/2

x=-5.5

Answer:

-11/2 or 5.5

Step-by-step explanation:

Find the product of the complex number and its conjugate.1 + 2i

1 - 4i
-3
5
1 + 4i

Answers

Answer:

The answer would be 5!

Step-by-step explanation:

You start with 1+2i and the conjugate of this would be 1-2i!

After that, in order to find the product, you multiply (1+2i)(1-2i)

You can use distribution or you can use the formula (a+b)(a-b)=a^2-b^2

Either way the answer will be 1-4i^2

i^2=-1 so you replace the i^2 in our equation with negative 1 and solve to get 5!

Hope this helped! <3

-1 6/15 - 7 3/10
what is it as a fraction and decimal

Answers

MODERATOR :    PLEASE DELETE

I don't wish to answer this question at this time.

Dylan got his math test back and saw a -12 1/2 points on the top of his math test. The grade was 100% because he earned extra credit points. How much extra credit did Dylan receive on his math test?

Answers

Since he got 100 percent, that means he didn't lose any points overall on his test. Since it said he lost 12 1/2 points, Dylan got 12 1/2 points back.

Find the eccentricity of 8x^2 + 6y^2 - 32x + 24y + 8 = 0

Answers

1) 
x 2 + y 2 - 10x - 8y + 1 = 0. 
(x^2-10x+25-25) +(y^2-8y+16-16) + 1 = 0 
(x-5)^2 -25 + (y-4)^2 -16 + 1 = 0 
(x-5)^2+(y-4)^2 = 40 

center (5,4); radius = sqrt(40) 

2) 
8x^2+ 6y 2 - 32x + 24y + 8 = 0. 
8(x^2-4x+4-4) +6(y^2+4y+4-4) +8=0 
8(x-2)^2 -32 + 6(y+2)^2 -24 + 8 = 0 
8(x-2)^2+6(y+2)^2 = 48 
divide throughout by 48 
(x-2)^2 /6 + (y+2)^2 /8 = 1 

Ellipse with center (2,-2) 
a=sqrt(6) 
b=sqrt(8) 
c^2= 8-6 = 2 
c= sqrt(2) 
eccentricity = c/a = sqrt(2)/sqrt(6) 

3) 
y=x^2-12x+36-36 
y=(x-6)^2 - 36 
Vertex is (6,-36) 

(x-h)^2=4p(y-k) 
(x-6)^2 = 4p(y+36) 
4p=1 
p=1/4 
focus : (h, k+p) = (6, -36+1/4) = (6, -143/4) 

4) 
focus lies on a vertical line, so the major axis is parallel to the y-axis 
(x-h)^2/a^2 +(y-b)^2/b^2 = 1 
h=-2 
k=0 
(x+2)^2/a^2+y^2/b^2 = 1 
2b=20 
b=10 
b^2=100 
(x+2)^2/a^2 +y^2/100 = 1 


e=c/a 
c/a = 4/5 
c=(4/5) a 
c^2 = 16/25 a^2 
c^2 = b^2-a^2 
(16/25) a^2 = 100 - a^2 
a^2(16/25+1) = 100 
41a^2/25 = 100 
a^2=2500/41 
a= sqrt(2500/41) 

(x+2)^2/a^2 +y^2/100 = 1 
(x+2)^2 /[2500/41] + y^2/100 = 1