Pl help heres the ss for it

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Find the number of sides of the regular polygon when the measure of an exterior angle is given.1. 30°
2. 10°

Answers

$1.\nexterior\angle=30^\circ\n exterior\angle=180^\circ-interior\ angle\n interior\angle=180^\circ-exterior\ angle=180^\circ -30^\circ=150^\circ\n \nFormula\ for\ number\ of\ sides\ of\ regular\ polygon:\n\n interior\angle= 180^\circ-(360^\circ)/(n)\n 150^\circ=180^\circ-(360^\circ)/(n)\n -30^\circ=-(360^\circ)/(n)\ |*n\n -30^\circ\ *n=-360^\circ \ |:-30^\circ\n n=12\n\n Number\ of\ sides\ is\ 12.$ $2.\nexterior\angle=10^\circ\n exterior\angle=180^\circ-interior\ angle\n interior\angle=180^\circ-exterior\ angle=180^\circ -10^\circ=170^\circ\n \nFormula\ for\ number\ of\ sides\ of\ regular\ polygon:\n\n interior\angle= 180^\circ-(360^\circ)/(n)\n 170^\circ=180^\circ-(360^\circ)/(n)\n -10^\circ=-(360^\circ)/(n)\ |*n\n -10^\circ\ *n=-360^\circ \ |:-10^\circ\n n=36\n\n Number\ of\ sides\ is\ 36.$

How much would it cost to make a million if I saved $100 everyday for a year

Answers

If you saved $100 everyday for a year you’d only get $365,000 so it would take 2 years and 270 days equaling $1,000,000

At a 25% off sale, a shirt cost $36.00. what was the regular price of the shirt?

Answers

36.00 / 75% = 0.48

0.48 x 100% =$48.00

Since the shirt is 75% of the regular price you would divide 36/75 which gives you .48 and then you times that by 100 which equals
48 dollars

Sara has 15 apples and 12 oranges. How many pieces of fruit does she have?

Answers

27 pieces o' fruit!!!!
15 + 12 = 27

15apples 12oranges
15 + 12 = 27 apples

A) SSS
B) SAS
D) ASA
E) AAS
F) HL
G)not congruent

Answers

Answer: E) AAS

Explanation:

AAS stands for Angle Angle Side. The order is important because the side is not between the angles.

The diagram shows that

angle A = angle D
angle C = angle F
side AB = side DE

Items 1 and 2 above correspond to the "A"s of "AAS", while item 3 refers to the "S".

Once again, the order of AAS is important. We don't go for ASA because side AB is not between angles A and C. Same for DE not between angles D and E.

Find the quadratic function y = a(x-h)^2whose graph passes through the given points (6, -1) and (4, 0). a) y = 1/4(x-5)^2 b) y = 1/4(x-5)^2 c) y = -1/4(x-6)^2 d) y = 1/4(x-6)^2

Answers

Answer: -1/2x - 2.

Step-by-step explanation:

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is

AI-generated answer

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is y = -1/2x - 2.