Let 'c' be the number of children, 'a' be the number of adults and 's' be the number of students in the theater.
Since, there are total 750 people in the theater.
So, c + s + a = 750 (Equation 1)
Now, it is given that there were half as many adults as children and students combined.
So,
So,
Putting the value of "c+s" in equation 1.
a = 250
Now, it is given that the receipts totaled $4950 and it charges $5 for children, $7 for students, and $9 for adults.
So, (equation 2)
Since,
So,
Substituting the values of 's' and 'a' in equation 2, we get
So, c = 400
Therefore, there were 400 children at the theater.
Answer: 37
Step-by-step explanation:
First, we need to find what h(-8) is. We can do this by substituting and simplifying the given function.
Given:
h(x) = x² - 5x +7
Substitute:
h(-8) = (-8)² - 5(-8) +7
Square and multiply:
h(-8) = 64 + 40 +7
Add:
h(-8) = 111
Next, we can find one-third of this. To do this, we will multiply.
Multiply:
(1/3) * 111 = 37
Answer:
( 2/9 )
Step-by-step explanation:
Okay, so since the events A and B are independent, the probability that both of them do not occur is the product of their individual probabilities of not occurring.
The probability of event A not occurring, denoted as ( P(A') ), is equal to 1 minus the probability of A occurring. Similarly, the probability of event B not occurring, denoted as ( P(B') ), is equal to 1 minus the probability of B occurring.
So, ( P(A') = 1 - P(A) = 1 - 1/3 = 2/3 ) and ( P(B') = 1 - P(B) = 1 - 2/3 = 1/3 ).
Since A and B are independent, the probability that both A and B do not occur is simply the product of their individual probabilities of not occurring:
[ P(N = 0) = P(A' cap B') = P(A')P(B') = (2/3) times (1/3) = 2/9 ]
So, the probability that no events occur is ( 2/9 ).
Hope this helps! :)
Answer:
The lowest common denominator for parts of a dozen is 12.
Step-by-step explanation: