The equation of line passes through points and in standard form is .
Further explanation:
It is given that a line passes through points and .
The slope of a line passes through points and is calculated as follows:
......(1)
Here, the slope of a line is denoted as and points are and .
Substitute for , for , for and for in equation (1) to obtain the slope of a line that passes through points and .
Therefore, the slope is .
The point-slope form of the equation of a line with slope passes through point is represented as follows:
......(2)
Substitute for , for and for in equation (2) to obtain the equation of line.
Therefore the standard equation of line that passes through points and is .
Thus, theequation of line passes through points and in standard form is
Learn more:
1. Which classification best describes the following system of equations? brainly.com/question/9045597
2. What is the value of in the equation when ? brainly.com/question/3965451
3. What are the values of x?brainly.com/question/2093003
Answer Details:
Grade: Junior High School
Subject: Mathematics
Chapter: Coordinate Geometry
Keywords:Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics,equation of line, line, passes through point
Answer:
x=-22
Step-by-step explanation:
6(x+15)=-42
6x+90=-42
6x=-132
x=-22
The range of the data is 4.2
The range in statistics for a given data set is the difference between the highest and lowest values.
Given:
2.2, 0.3, -1.5, 2.6, 1.9, 0.4, 0.6, -1.6, 2.5, -0.6
Arranging the data in some order
-1.6 , -1.5, -0.6, 0.3, 0.4, 0.6, 1.9, 2.2, 2.5, 2.6
So, range
=highest data - lowest data
=2.6 - (-1.6)
=2.6+1.6
=4.2
Hence, the range is 4.2.
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Answer:
The range is -4.2
Step-by-step explanation:
Least to Greatest:
-1.6
-1.5
-0.6
0.3
0.4
0.6
1.9
2.2
2.5
2.6
Subtract Least Number from Greatest Number
-1.6 - 2.6
=-4.2
b. 22
c. 24
d. 25
In the sequence 0, 3, 8, 15, a5, 35, the term a5 equals 24 as each term in the sequence is the square of its position minus 1.
To determine the value of a5 in the sequence 0, 3, 8, 15, a5, 35,... let's first analyze the pattern in the sequence. Each term equals the square of the term's position in the sequence minus 1. This implies that the first term is (1²-1)=0, the second term is (2²-1)=3, the third term is (3²-1)=8, and so on. Hence, the fifth term a5 would be (5²-1)=24. So, the answer is c. 24.
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