70 ans 20 in simplest fore in ratios

Answers

Answer 1

Answer: Assuming that you just made a typo the answer would be 7:2

Both numbers are divisible by 10, and 7 and 2 share no common factors as they are both prime numbers making it the most simplified

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The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?The domain is all real numbers. The range is {y|y < 16}. The domain is all real numbers. The range is {y|y ≤ 16}. The domain is {x|–5 < x < 3}. The range is {y|y < 16}. The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}.
(PLS HELP!!!!!!) Answer for a then b

An alloy weighing 40 lbs. is 10% tin. The alloy was made by mixing a 15% tin alloy and a 8% tin alloy. How many pounds of each alloy (to the nearest tenth) were used to make the 10% alloy?lbs. of the 15% alloy and lbs. of the 8% alloy.

Answers

Let the weight of 15% tin be x.

So the weight of the 8% tin will be: (40 - x), since the total weight is 40 lbs

Using the mixture formula:

w1*p1 + w2*p2 = w*p

Where w1 = weight of the first percentage, p1 = First Percentage

w2 = weight of the second percentage, p2 = Second Percentage

w = Final weight, p1 = Final Percentage

0.15*x + 0.08(40 - x) = 40*0.1

0.15x + 3.2 - 0.08x = 4

0.15x - 0.08x = 4 - 3.2

0.07x = 0.8

x = 0.8/0.07

x ≈ 11.429

Recall the 15% was made with x, which is ≈ 11.429

Recall the 8% was made with (40-x) ≈ (40 - 11.429) ≈ 28.571

So the 10% tin of the 40 lbs was made with ≈11.4 lbs of the 15% tin and ≈28.6 lbs of the 8% tin

x=15% alloy
y=8% alloy
x+y=40
y=40-x
0.15x+0.08y=40*0.10
0.15x+0.08(40-x)=40*0.1
times 100 both sides for easy
15x+8(40-x)=400
15x+320-8x=400
7x+320=400
minus 320 from both sides
7x=80
divide both sides by 7
x=80/7
x+y=40
80/7+y=280/7
y=200/7
aprox
x=11.4lb
y=28.6lb

11.4lb of 15%
28.6lb of the 8%
what????

Find the area of the parallelogram by composing into rectangles or decomposing into triangles or other shapes as needed. 8 yd 6 yd 15 yd10 yd

Answers

Answer:

Below.

Step-by-step explanation:

The area = area of a rectangle on the same base and between the same parallel lines

= (15 + 6) * 8

= 21 * 8

= 168 yd^2.

Answer:

160

Step-by-step explanation:

First, you add 15 + 6 multiplied by 8.

Expression (15 + 6) x 8=?

First, add the expression in the prentice.

15 + 6= 21

Cut out the 10. Why? Because it says make it a triangle. If u did it the other

way it wouldn't make sense.

then multiply 21 and 8

that gives you 160

a community hall is in the shape of a cuboid. the hall is 20m long, 15m wide and 4m high. the community hall needs re-decorating with new paint for the walls and ceiling, and new tiles on the floor. a 20l tin of paint covers 40 squared metres and costs £15. 1 squared metre floor tiles cost £3 each. work out the total cost of paint and tiles needed to decorate the community hall.

Answers

Answer:

the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.

Step-by-step explanation:

Area of the walls:

- The community hall is shaped like a cuboid, so the walls are the four rectangular sides.

- The length and height of each wall are given as 20m and 4m, respectively.

- The total area of the walls is the sum of the areas of all four walls: 2 * (length * height + width * height).

- Substituting the given values, we have: 2 * (20m * 4m + 15m * 4m).

2. Area of the ceiling:

- The ceiling is also a rectangle, with the same length and width as the floor.

- The area of the ceiling is given by length * width: 20m * 15m.

3. Area of the floor:

- The area of the floor is the same as the area of the ceiling: 20m * 15m.

Now, let's calculate the areas:

1. Area of the walls:

- 2 * (20m * 4m + 15m * 4m) = 2 * (80m^2 + 60m^2) = 2 * 140m^2 = 280m^2.

2. Area of the ceiling:

- 20m * 15m = 300m^2.

3. Area of the floor:

- 20m * 15m = 300m^2.

Next, we can calculate the number of tins of paint and tiles needed and their costs:

- Number of tins of paint needed = Area of walls / Coverage per tin = 280m^2 / 40m^2/tin = 7 tins.

- Cost of paint = Number of tins * Cost per tin = 7 tins * £15/tin = £105.

- Number of tiles needed = Area of floor / Area per tile = 300m^2 / 1m^2/tile = 300 tiles.

- Cost of tiles = Number of tiles * Cost per tile = 300 tiles * £3/tile = £900.

Therefore, the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.

yes, i am a student

a cereal box is 8 1/2 inches long, 3 1/2 inches wide, and 12 inches high. what is the volume of the the box?

Answers

Length of the cereal box = 8 1/2 inches
= 17/2 inches
Width of the cereal box = 3 1/2 inches
= 7/2 inches
Height of the cereal box = 12 inches
Then
Volume of the cereal box = Length * Width * Height
= (17/2) * (7/2) * 12 cubic inches
= 17 * 7 * 12 cubic inches
= 1428 cubic inches

I think its 357 squared. Just multiply all of it together. I'd check the formula for finding volume if you want a reliable answer

6x + 2y = 10 in slope intercept form

Answers

Answer:

y = -3x + 5

Step-by-step explanation:

Slope intercept form is y = mx + b.

To solve this, you have to rearrange the equation to leave y alone.

First, you have to subtract 6x from both sides, so 2y is alone.

6x - 6x + 2y = 10 - 6x

2y = -6x + 10

Then, you have to divide both sides by 2, so y is alone.

2y/2 = (-6x/2) + (10/2)

y = -3x + 5

Hope this helps!

You have 5,814 feet of rope that you need to cut into 27-foot sections. How many sections of rope will you have?a. 215 sections with 8 feet left over
b. 215 sections with 9 feet left over
c. 218 sections with 3 feet left over
d. 215 sections with 3 feet left over

Answers

The answer is d. 215 sections with 3 feet left over

To calculate this, divide the length of the rope (l1) by the length of the section (l2).
n - number of sections

n = l1/l2
l1 = 5,814 ft
l2 = 27 ft

n = 5,814 / 27 = 215.3 sections
215.3 sections can be written as 215 (whole) sections with 3 ft left over.

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