MATHEMATICS HIGH SCHOOL

Please help asap Make sure to draw a table to visualize your data.You can use desmos to check your answers as well.
When putting in the function into desmos, you must put it as (ex: y=30000*(1.04)^x)
Desmos does not recognize other letters than x and y.
Please help asap Make sure to draw a table to - 1

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Related Questions

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Simplify the following

Square root 15 / Square root 3

Answers

Answer:

The answer is √5 .

Step-by-step explanation:

Youhavetorationalizethefractioninordertogetridofsurdinthedenorminatorbymultiplying√3tobothnumeratoramddenorminator:

( √(15) )/( √(3) )

= ( √(15) )/( √(3) ) * ( √(3) )/( √(3) )

= ( √(15) * √(3) )/( √(3) * √(3) )

= ( √(45) )/(3)

= ( √(9 * 5) )/(3)

= (3 √(5) )/(3)

= √(5)

Which of the following expresses the ratio of 3 inches to 2 yards?(A) 3 : 12
(B) 3 : 72
(C) 3 : 9
(D) 3 : 24
(E) 3 : 2

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1\ yard=36\ inches\n ratio:3\ inches:2\ yards\n 2\ yards=72\ inches\n \n ratio: 3:72[inches]\n The\ correct\ answer\ is\ B.

Answer:

E

3 :2

if inhes

then D

How is the interquartile range calculated?A. Find the difference between the values for quartile 3 and quartile 1.
B. Find the difference between the values for the maximum and minimum.
C. Find the difference between the values for quartile 2 and quartile 1.
D. Find the difference between the values for the maximum and median.

Answers

It is the difference between the third and the first quartile

Answer:

find the difference between the values for quartile 3 and quartile 1

Step-by-step explanation:

Just got it right on APEX

PLZ HELP ME understand

factor each expression
5r{2}+23r+26

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Get the app photo math solved your problem

Jesse is planting a vegetable garden. The area of the garden is 16 square yards. Each vegetable plant will need 1/9 of a square yard to grow in. How many vegetable plants will Jesse be able to plant in her garden?

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Answer:

its 144

Step-by-step explanation:

Determine the type and number of solutions of 4x^2-5x+1=0.A. Two real solutions
B. One real solution
C. Two imaginary solutions

Answers

4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9

x = - b ± √Δ / 2.a
x = (-5\± √(9) )/(2*4)
x = (-5\±3)/(8)
x' = (-5-3)/(8) = (-8)/(8) = -1
x' = (-5+3)/(8) = (-2)/(8) (/2) = (-1)/(4)


A. Two real solutions (x' = -1 and x'' = -1/4)
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