MATHEMATICS HIGH SCHOOL

Francine Flicka found a bargain when she bought a lawn mower. She paid the store's clerk three $20 bills and received him $7.45 in change. If the sales tax is 7.3%, what was the selling price of the mower before taxes? $56.39

$53.55

$52.55

$48.97

Answers

Answer 1

Answer:

Answer:

$48.97

Step-by-step explanation:

Let p represent the marked price of the mower. Then the price with tax is ...

with tax = p + 7.3%×p = 1.073p

The amount Flicka paid is the amount tendered less the change she received, so is ...

3×$20 - 7.45 = with tax = 1.073p

To find p, we can divide by its coefficient:

(3 × $20 - 7.45)/1.073 = p ≈ $48.97

The selling price before taxes was $48.97.

_____

Comment on the problem

If you check the answer, you find the amount with tax is ...

$48.97 × 1.073 ≈ $52.54481 ≈ $52.54

so the change Flicka would have received would have been $7.46, not $7.45. If the price were $48.98, then the change would have been $7.44. There is no price at which the mower can be marked that will make the total with tax come to $52.55. There is no solution to this problem.

Answer 2

Answer:

Answer:

$48.97

Step-by-step explanation:

She paid three $20 bills

3 × 20 = $60

She received $7.45 change

60 - 7.45 = $52.55

The mower was for $52.55 with sales tax.

The sales tax is 7.3%.

Before the sales tax (reduce tax).

52.55 × (1-7.3%)

= $48.97

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What is f(x)=x2-5 btw that 2 is square

Answers

Answer:

sqrt 5 = 2.23606798

Step-by-step explanation:

Thank you for telling us the 2 is squared that really helps!

x^2 - 5 = 0

(add 5 both sides)

x^2 = 5

(sqrt both sides) (sqrt stands for square root)

x = sqrt 5

(Usally they just want sqrt 5 as an answer but if they want decimals its)

x = 2.23606798

Answer:

x= $√(5)$

Step-by-step explanation:

f(x)= $x^(2)$ -5

$x^(2)$ -5=0

Add 5 to both sides.

$x^(2)$ =5

To get rid of the square of x, put the square root thingie so that it will cancel out. BTW, if you put it on one side, you have to put it on the other side.

$\sqrt{x^(2) }$ = $√(5)$