As per the question no (a) The areas corresponding to each other are triangles ABC and DEF, and the common ratios are AB/DE = 5/2 and BC/EF = 5/2. Lets find the solution :-
Now,
In triangles ABC and DEF, we have the following:-
∠A and ∠D are congruent, so we can say ∠A = ∠D.
∠C and ∠F are congruent, so we can say ∠C = ∠F.
Now, to find which areas correspond, let's compare the ratios of corresponding sides:-
AB/DE = 15/6 = 5/2
BC/EF = 20/8 = 5/2
These ratios are equal, indicating that sides AB and DE correspond, and sides BC and EF correspond. So, the areas corresponding to each other are triangles ABC and DEF, and the common ratios are AB/DE = 5/2 and BC/EF = 5/2.
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9+2= 711
8+5- 313
5+2= 37
7+6= 113
9+8= 117
10+6= 416
15+3= 1218
Answer:
To solve the system of equations using elimination, we need to eliminate one variable by adding or subtracting the equations. Let's start by rearranging the first equation in standard form:
2x - 7y = 16
Next, let's rearrange the second equation so that both equations have the same number of x or y terms:
3y = 7 - x
We can rewrite this equation as:
x + 3y = 7
Now we have the following system of equations:
2x - 7y = 16
x + 3y = 7
To eliminate the y variable, we can multiply the second equation by 7:
7(x + 3y) = 7(7)
This gives us:
7x + 21y = 49
Now we can subtract the first equation from this equation:
(7x + 21y) - (2x - 7y) = 49 - 16
Simplifying the equation gives us:
7x + 21y - 2x + 7y = 33
Combining like terms, we get:
5x + 28y = 33
Now we have a new equation with only x and y terms. We can solve for one variable and substitute it back into either of the original equations to find the value of the other variable.
Step-by-step explanation:
Answer:
yes
Step-by-step explanation: