A paroxysm of laughter escaped a few. If the ratio of the laughers to the stolid was 2 to 17,and 7600 were in the throng, how many did not laugh

Answers

Answer 1

Answer: Well, one part is 3800 so the remaining 17-2=15 parts was 57000 people.

Related Questions

Richelle drew a hexagon KLMNOP at the right. She thinks the hexagon has six congruent angles. How can she show that the angles are congruent without using a protractor to measure them?
True or False: For the depreciation formula, A = C(1 - r)t, the A value will always be greater than the C value.
Simplify completely: 3x+18 / 181) x2) 3x3) x+6 / 64) x+18 / 6 ...?
Divide the following
7.8+ (x-18)=31 Please Help Asapty

Find the inverse of each function1) g (x)= 3+(x-1)^3
4) f (x)=x^3+2
5) f (n)= 5 square root of (-n+1/2)

Answers

to find the inverse
1. replace f(x) or g(x) or f(n) with y
2. switch places of x and y
3. solve for y
4. replace y with f⁻¹(x) or g⁻¹(x) or f⁻¹(n)

1.
g(x)=3+(x-1)^3
replace
y=3+(x-1)^3
switch
x=3+(y-1)^3
solve
x=3+(y-1)^3
subtract 3
x-3=(y-1)^3
cube root both sides
$\sqrt[3]{x-3}$ =y-1
add 1
$\sqrt[3]{x-3}$ +1=y
switch y with g⁻¹(x)
g⁻¹(x)= $\sqrt[3]{x-3}$ +1

4. f(x)=x^3+2
replace with y
y=x^3+2
switch x and y
x=y^3+2
solve for y
x=y^3+2
subtract 2
x-2=y^3
cube roo both sides
$\sqrt[3]{x-2}$ =y
replace with f⁻¹(x)
f⁻¹(x)= $\sqrt[3]{x-2}$

5.
f(n)=5 $√(-n+1/2)$
replace
y=5 $√(-n+1/2)$
switch n and y
n=5 $√(-y+1/2)$
solve for y
n=5 $√(-y+1/2)$
divide both sides by 5
n/5=n= $√(-y+1/2)$
square both sides
$(n^2)/(25)$ =-y+1/2
subtract 1/2 from both sides
$(n^2)/(25)$ - $(1)/(2)$ =-y
multiply both sides by -1
- $(n^2)/(25)$ + $(1)/(2)$ =y
replace with f⁻¹(n)
f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

1. g⁻¹(x)= $\sqrt[3]{x-3}$ +1
4. f⁻¹(x)= $\sqrt[3]{x-2}$
5. f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

M(x) =5
Find m(2)
I have no idea how to do this help me

Answers

Answer:

Step-by-step explanation:

All this is saying is when there is one x value it is equal to 5

so, applying that logic, 2 fives is equal to 2*5=10

so when x=2, it is equal to 10

Hope this helps you out!!!

if x = 5 then m(2)= 10

In a right triangle, if the length of the hypotenuse is 5 and the length of one of the other sides is 3, what is the length of the third side?

Answers

Answer:

a^2+b^2=c^2

a^2+9=25(5*5)

therefore ,a^2=25-9=16

√16=4

sides are 4 cm,3 cm,5 cm

Step-by-step explanation:

$4.$

Step-by-step explanation:

Pythagoras theorem says that "In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides". As the Hypotenuse side is already yet given and one of the side of a triangle value is given. Now we should find the value for other side of a triangle. In order to find the value of other side, we should use the Pythagoras theorem formula.

AC²=AB²+BC²

Let AC be the Hypotenuse side, AB and BC be the other two sides of a triangle.

Given:-

AC=5,AB=3,BC=?

Use Pythagoras theorem formula

AC²=AB²+BC²

5²=3²+BC²

25=9+BC²

25-9=BC²

16=BC²

√16=BC

BC=4.

(x^-4)^5
please simplify the expression

Answers

$(x ^(-4) )^(5)$

Apply exponent rule :

$(a^b)^c = a^ ^(b.c)$

$=x ^((-4)*5)$

$(-4)*5$

$= - 20$

Apply exponent rule :

$a ^(-b) = (1)/(a^b)$

$= (1)/(x ^(20) )$

hope this helps!

Describe the relationship between the lengths of yx and yw