Answer:
A. <1
D. <4
F. <8
Step-by-step explanation:
Given that lines l and m that are crossed by transversal t, the following angles are congruent to <5:
<8 = <5 (vertical angles)
<1 = <5 (corresponding angles)
<4 = <5 (alternate interior angles)
Therefore, the angles that are congruent to <5 are labelled <8, <1, and <4.
The angles congruent to a given angle in a set of parallel lines intersected by a transversal are the corresponding angle, the alternate interior angle, and the alternate exterior angle on the other side of the transversal.
In geometry, when two lines are parallel (l || m) and intersected by a transversal (t), the angles that are formed have certain relationships. Here, if one angle measures 25 degrees, then the angles congruent (equal in measure) to this angle are: the corresponding angle on the other side of the transversal, the alternate interior angle on the other side of the transversal, and the alternate exterior angle on the other side of the transversal. This is because parallel lines cut by a transversal create corresponding angles, alternate interior angles, and alternate exterior angles that are all congruent.
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Think of it like saying 32 < 35. Then stick a decimal point in front of each number.
Answer:
airplane will over shoot the runway by 100 miles (for USA Test Prep people)
Step-by-step explanation:
slope =
25,000 - 19,000
150 - 90
= 100
y = mx + b
25,000 = 100(150) + b
25,000 - 15,000 = b
b = 10,000
thus,
y = mx + b
0 = 100x + 10,000
-10,000 = 100x
x = -100
When the plane is at ground level (y = 0), it will be 100 miles past the end of the runway.
Answer: Value of tenth term of the geometric sequence is 1536.
Step-by-step explanation:
Since we have given that
3, 6, 12, 24, 48, …
Since it is a geometric sequence.
So, here ,
a = first term = 3
r= common ratio is given by
We need to find the tenth term of the geometric sequence.
As we know the formula for "nth term ":
Hence, Value of tenth term of the geometric sequence is 1536.
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a12=-16+(2×12)=
-16+24=8
Answer:
Step-by-step explanation:
C=(5,-3)
P=(3,2)
PC²=(3-5)²+(2+3)²=29
29>25 =P is exterior to the circle