Answer:
Explanation:
Cylinder P is taller than cylinder Q. In fact, it's twice as tall. So if cylinder Q is, let's say, 10 inches tall, cylinder P would be 20 inches tall.
Cylinder P is also wider, but not by a lot. It's only half as wide as cylinder Q. So if cylinder Q has a width of 10 inches, cylinder P would have a width of 5 inches.
Now, let's talk about the insides of these cylinders, how much stuff they can hold. If we filled them up with something, like water, the bigger one (cylinder P) can hold twice as much as the smaller one (cylinder Q).
So, cylinder P can hold more stuff because it's both taller and a little wider than cylinder Q.
b. Find the ball’s range from question 2.
Answer:
2.57 s
8.12 m
46.4 m
Explanation:
1. In the y direction:
s = 0 m
u = 22 sin 35° m/s = 12.6 m/s
a = -9.8 m/s²
Find: t
s = ut + ½ at²
0 = (12.6) t + ½ (-9.8) t²
t = 2.57 s
2. In the y direction:
u = 12.6 m/s
v = 0 m/s
a = -9.8 m/s²
Find: s
v² = u² + 2as
0² = (12.6)² + 2 (-9.8) s
s = 8.12 m
3. In the x direction:
u = 22 cos 35° m/s = 18.0 m/s
a = 0 m/s²
t = 2.57 s
Find: s
s = ut + ½ at²
s = (18.0) (2.57) + ½ (0) (2.57)²
s = 46.4 m
Answer:
All of the above
Explanation:
According to Newton's second law of motion,
If a certain force is applied on objects of different mass, the lighter object will travel farther and faster. All the options in the question have pairs where one object is lighter than other.
So, Jim can throw a tennis ball farther than a basketball. Jim can throw a can of soda farther than a liter bottle of soda and he can throw a chair farther than a couch.
B. 0.004021624m3
C. 0.002021624m3
D. 0.000010812m3
As per the question the volume of mercury is given as 0.002 m^3 at 20 degree Celsius.
We are asked to calculate the volume of the mercury at 50 degree Celsius.
This problem is based on thermal expansion of matter.
Let us consider the initial and final volume of the mercury is denoted as -
Let the initial and final temperature of the mercury is denoted as -
As per question
The change in temperature is
Mercury is a fluid.So we have to apply volume expansion of liquid .
The coefficient of of volume expansion of mercury at 20 degree Celsius is 0.00018 per centigrade.
As per volume expansion of liquid,
Here is the volume at T degree Celsius.
Hence volume at 50 degree Celsius is calculated as-
[ans]
As per the options given in the question ,option A is close to the calculated value. So option A is right.