Which of the following is a region where magnetic force will affect other magnets?A-electronic domain
B- magnetic generator
C- magnetic field
D- magnetic charge

Answers

Answer 1

Answer: it is c.......ik bc i just got it right on platoweb

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Light of wavelength 550 nm falls on a slit that is 3.50 x 10^-3 mm wide. How far from the central . maximum will the first diffraction maximum fringe be if the screen is 10.0 m away?

Answers

λ $= 550 * 10^(-9)\] m. D = 3.50*10^-6 m.$
$d = 10 m. m = 1 2x = ?$

Then you need to find x when n=1
or
$sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4$
≈θ for θ<<1 , so θ= $1.59x10^-4 radians$

Then you can find rhe distance of bright fringe from the center: $d= θD=1.59x10^-4x10m ≈ 1.6 mm$

Which refers to the rate of change in velocity?speed
O acceleration
O direction
O magnitude

Answers

The answer is obvious acceleration lol sorry if it sounds mean

What has the same relationship to circle : cylinder?

Answers

Circle is a plane figure ( flat , 2-dimensional)

meanwhile, cylinder is a solid figure ( 3-dimensional, can be filled with volume)

They both have the same relationship because in order to build a cylinder , you need two circles ( at the top and the bottom), and the size of that circles will directly affected the cylinder's volume

A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?

Answers

1. If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.

Answer:

height=2

Explanation:

MA= input/output

MA= 5

input = 10 (the ramp)

output=x (the height)

5=10/x

x=2

You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?

Answers

Answer:

2m/s

Explanation:

speed = distance÷time

speed =90÷45=2m/s

Find the percentage of the total work lost to friction if 28.7 J of work is put into pushing a block up a ramp resulting in 14.2 J of stored potential energy at the top.