a) Yes, The average speed of the train could have been greater than 145 km/h,
b) the new maximum average speed, correct to 2 decimal places, is approximately 2.46 km/minute.
a) To determine if the average speed of the train could have been greater than 145 km/h, we need to calculate the maximum possible average speed given the track length rounded to the nearest 10 km.
The track length is 290 km, rounded to the nearest 10 km. This means the actual track length could be anywhere between 285 km (290 km - 5 km) and 295 km (290 km + 5 km).
To find the maximum average speed, we'll assume the train took the minimum possible time (120 minutes) to cover the maximum possible track length (295 km):
Maximum Average Speed = (Maximum Possible Track Length) / (Minimum Possible Time)
Maximum Average Speed = 295 km / 120 minutes ≈ 2.4583 km/minute (rounded to 4 decimal places)
Since 2.4583 km/minute is greater than 145 km/h (which is approximately 2.4167 km/minute), the answer is:
Yes, the average speed of the train could have been greater than 145 km/h.
b) Now that we know the track was measured to the nearest 5 km, we'll calculate the new maximum average speed in km per minute based on the maximum possible track length (295 km) and the minimum possible time (120 minutes):
Maximum Average Speed = (Maximum Possible Track Length) / (Minimum Possible Time)
Maximum Average Speed = 295 km / 120 minutes ≈ 2.4583 km/minute (rounded to 4 decimal places)
So, the new maximum average speed, correct to 2 decimal places, is approximately 2.46 km/minute.
Learn more about average speed here:
#SPJ1
Answer:
SSS
Step-by-step explanation:
B. 52
C. 30
D. 50
x = 5
y = 7
x = 7
Answer:
y = 7
Step-by-step explanation:
x=4 is a vertical line that goes through the point x=4. y value of this graph changes while x value will be 4 at every point of the graph.
A line perpendicular to this will be a horizontal line with a fixed y value and the x value will change.
The coordinates of the point of which the line has to pass is given as (5,7). Which means the y coordinate of this line is 7.
As we have established that this line has to have same y value at each point just like x=4 has same x value at each point, we can say the equation of the line is y=7.
Solution:
Equation of line perpendicular to , x=4 is
y +k=0
As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0
As, given the line perpendicular to, x =4, passes through the point (5,7).
So, y+k =0, passes through (5,7).
→ 7 +k=0
→ k= -7
So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.
Option (C) →y=7
parents work outside the home spends 20 hours a week watching television. The
population mean = 20 and the standard deviation of the distribution is equal to 5.
Calculate the z-scores for the following individual times:________
If X = 5, z= ________
If X = 37, z= ________
Answer: If X = 5, z=-3
If X = 37, z= 3.4
Step-by-step explanation:
We know that the formula to find the z-score for any random variable x is given by :-
, where = Population mean
= Population standard deviation.
As per given , we have
Then , the z-score for x =5
i.e. If X = 5, z=-3
When x =37,then
i.e. If X = 37, z= 3.4