MATHEMATICS HIGH SCHOOL

What would be the cost for 5 of the cost for 5 of the gift cards a $80
b $90
c$100
d$110
what would be the cost for 5 of the cost - 1

Answers

Answer 1
Answer:

Answer:

Cost for the 5 gift cards = $20

Step-by-step explanation:

In the given graph,

y axis shows the "total cost" in dollars

x axis shows the "number of gift cards"

According to the graph:

Cost of 1 card    = $20

Cost of 2 cards = $40

Cost of 3 cards = $60

Cost of 4 cards = $80

We see that that relation represents the linear relation.

So, cost of 5 cards = 5*$20 = $100

That's the final answer.

I hope it will helps you.
Answer 2
Answer: the table shows that 1 gift card equals 20 dollars... so 20 * 5 = 100
so your answer is C.) $100

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The minimum monthly payment for Alicia's credit card is 2% of her balance or $10, whichever is higher. If Alicia's balance at the end of her last billing cycle was $470, what is her minimum monthly payment?

Answers

Answer:

Alicia's minimum monthly payment is $10.

Step-by-step explanation:

Given is :

Alicia's balance at the end of her last billing cycle was $470. So, its 2 % becomes:

(2)/(100) *470 = $9.40

As it is stated that the minimum monthly payment for Alicia's credit card is 2% of her balance or $10, whichever is higher.

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2(2x - 4) + x = 7

whats x?

Answers

2(2x-4)+x=7
= 4x-8+x=7
= 4x+x-8=7
= 5x=7+8
= 5x=15                     dividing both sides by 5
= x=15/5
= x=3
so x is 3

The roots of x2 − ( ) + 34 are 5 ± 3i.

Answers

use quadratic formula
if you had ax^2+bx+c=0, then
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}
a=1
b=?
c=34
subsitute
\frac{-b+/- \sqrt{b^(2)-4(1)(34)} }{2(1)}=5+/-3i
\frac{-b+/- \sqrt{b^(2)-136} }{2}=5+/-3i
make 5+/-3 into fraction over 2,(10+/-6i)/2
\frac{-b+/- \sqrt{b^(2)-136} }{2}=(10+/-6i)/2
multiply both sides by 2
-b+/- \sqrt{b^(2)-136}=10+/-6i
we conclude that -b=10
b=-10

ok so equaton is
x^2-10x+34

The roots of  x² -bx+34=0  are 5 ± 3i.  Then b = ?

-------------------

Vieta's formulas :

5 - 3i + 5 + 3i = b ⇒ b =10 

Now, we have the equation:

x² -10x + 34 = 0 

What is the length of each side of a square that has the same area as a rectangle that has a length of 12.2 in. and a width of 16.6 in.?Round to the nearest tenth.

Answers

Area of the rectangle= l*w
Area of the rectangle= 202. 52 square inches

Area of the square={202.52} 
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Benone would finish mower garden in 8 hours. Pandele would finish in 10 hours mowing same garden. How long would finish mower garden together?

Answers

Benone-(1)/(8)\ mower\ garden\ per\ hour\n\nPandele-(1)/(10)\ mower\ garden\ per\ hour\n\n(1)/(8)+(1)/(10)=(*)\n\nfind\ LCD((1)/(8);\ (1)/(10))\n\nList\ of\ the\ multiples\ of\ 8:0;\ 8;\ 16;\ 24;\ 32;\ \boxed{40};\ 48;...\nList\ of\ the\ multiples\ of\ 10:0;\ 10;\ 20;\ 30;\ \boxed{40};\ 50;\ ...\n\nLCD((1)/(8);\ (1)/(10))=40\n\n(1)/(8)=(1\cdot5)/(8\cdot5)=(5)/(40);\ (1)/(10)=(1\cdot4)/(10\cdot4)=(4)/(40)

(*)=(5)/(40)+(4)/(40)=(9)/(40)-together\ per\ hour

t-time\ when\ together\ finish\ the\ garden\n\n(9)/(40)\cdot t=1\ \ \ \ \ \ |multiply\ both\ sides\ by\ (40)/(9)\n\n\boxed{t=(40)/(9)\ (h)=4(4)/(9)\ h=4h+(4)/(9)h=4h+(4)/(9)h=4h+(4)/(9)\cdot60\ min\approx4h27min}
In 1 hour, Benone _ _ _ g / 8 ;
In 1 hour, Pandele _ _ _ g / 10 ;
= = = = = = = = = = = = = = = = =
In 1 hour, Benone and Pandele  _ _ _ g / 8 + g / 10 = 5g / 40 + 4g / 40 = 9g / 40;
Benone and Pandele would finish garden together in 40 / 9 hours = 4 hours 26 minutes 40 seconds;

A university's freshman class has 5000 students. 80% of those students are majoringin Computer Science. How many students in the freshman class are Computer
Science majors?

Answers

Answer:

4000 students

Step-by-step explanation:

Number of computer science majors = 80% of 5000

                                                              = 0.8 * 5000

                                                              = 4000

Answer:

4000

Step-by-step explanation:

5000 * .8 is 4000
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