In a scale drawing of a house, 1 inch represents 3 feet. (a)The length of the real house is 21 feet. What is the length of the house in the scale drawing? _ inches

Answers

Answer 1
Answer:

Answer:

7 inches

Step-by-step explanation:

divide 21 by 3


Related Questions

Simplify this expression: 4p + 9 + (–7p) + 2 = ?A. 11p + 11B. 3p + 11C. –3p + 11D. 3p + 7
The line passes through the points (x1, y1) and (x2, y2). The slope of the line is: a) x2−x1y2−y1​ b) y2−y1x2−x1​ c) x1−x2y1−y2​ d) y1−y2x1−x2​
What's the nearest tenth of 6.40
Determine whether the triangles are similar. If so, what are the similarity statement and the postulate or theorem used? A) traingleDGH~trianlgeDFE;SSS~B)trianlgeDGH~traingleDFE;SAS~C)trianlgeDGH~trianlgeFEG, SAS~D)The triangles are not similar
Can you go to grandmas estate and measures 8 inches across by 2 inches high if the actual stadium measures 500 feet across which equation can be used to find ex the height of the stadium in feet

When the equation a – bx = cx + d is solved for x, the result is x = .Use the general solution to solve 5 – 6x = 8x + 17.

Answers

The value of x in the equation a – bx = cx + d is = a - d / c + b

The value of x in the equation  5 – 6x = 8x + 17 is - 6 / 7

a - bx = cx + d

add bx to both sides of the equation

a - bx + bx = cx + bx + d

a = cx + bx + d

subtract d form both sides of the equation

a - d = cx + bx + d - d

a - d = cx + bx

Distributive law:

using distributive law on the right side of the equation

a - d = x (c + b)

divide both sides by (c + b)

Therefore,

x = a - d / c + b

Let's use the same method to solve 5 – 6x = 8x + 17

5 – 6x = 8x + 17

add 6x to both sides

5 – 6x  + 6x= 8x + 6x + 17

5 = 14x + 17

subtract 17 from both sides

5 - 17 = 14x + 17 - 17

-12 = 14x

divide both sides by 14

x = -12 / 14

x = - 6 / 7

learn more on equations here: brainly.com/question/7838122

If angle one and angle five a vertical angles and angle one equals 55° then angle five will equal _____?

Answers

55º

vertical angles are congruent

I need Help ASAP!
Please Help.

Answers