Step-by-step explanation:
1 and 2023 yes as standard.
2 no (not an even number).
3 no (sum of the digits is 7 and not divisible by 3).
4 no (not an even number)
5 no (2023 dies not end with 5 or 0)
6 no (not an even number)
7 yes. and therefore also 2023/7 = 289
7 has no other factors, so 289 is the remaining part with potentially other prime factors.
289 = 17², so 17 is another factor.
but 17 is again a prime number and has no other factors.
2023 = 7×17×17
and so, 7×17 = 119 is also a factor of 2023.
so, we have as factors :
1, 7, 17, 119, 289, 2023
that means 6 factorsin2023.
A) QR = 8
B) QR = -9
C) QR = 9
D) QR = 18
Explanation:
M is the midpoint of QR, so QM = MR, meaning that the two smaller pieces are equal (the two pieces combine back to QR)
Use substitution and isolate x
QM = MR
2x+5 = 5x-1
2x-5x = -1-5
-3x = -6
x = -6/(-3)
x = 2
If x = 2, then QM is
QM = 2x+5 = 2*2+5 = 9
and MR is
MR = 5x-1 = 5*2-1 = 9
both are 9 units long. Both are the same length as expected, so this helps confirm the answer.
The last thing we do is add up the two pieces QM and MR to get the length of QR. This is using the segment addition postulate.
QR = QM + MR
QR = 9 + 9
QR = 18
note: a negative length is never possible in any situation, so you can immediately eliminate choice B from the list of possible answers without even doing any math.
Answer:
I. A' = (5,-5), B' = (-1,6), C' = (6,1)
II. A' = (5,-11), B' = (-1,0), C' = (6,-5)
III. A' = (-5,-2), B = (6,4), C' = (1,-3)
Step-by-step explanation:
We are given the vertices of ΔABC as A = (2,-5), B = (-4,6) and C = (3,1).
I. It is required to 'reflect the triangle about the line x= 3'.
This rule changes (x,y) to (x+3,y).
So, the new vertices are given by,
A' = (2+3,-5) = (5,-5)
B' = (-4+3,6) = (-1,6)
C' = (3+3,1) = (6,1)
II. It is required to 'translate the triangle 3 units to the right and 6 units down'.
This rule changes (x,y) to (x+3,y-6).
So, the new vertices are given by,
A' = (2+3,-5-6) = (5,-11)
B' = (-4+3,6-6) = (-1,0)
C' = (3+3,1-6) = (6,-5)
III. It is required to 'rotate the triangle by 90° about the origin counter-clockwise'.
This rule changes (x,y) to (y,-x).
So, the new vertices are given by,
A = (2,-5) implies A' = (-5,-2)
B = (-4,6) implies B = (6,4)
C = (3,1) implies C' = (1,-3)
15
7