What is the correct line description for x+3y=1?

Answers

Answer 1

Answer: If you solve for y you get y = x/3 + 1/3. That's a line with slope 1/3 with a y intercept of 1/3.

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the sun is about 93x10 to the power of 6 miles from earth what this distance written as a whole number?

Answers

The x10 to the power of six part just means that there are six zeros. So, 93000000

If a rectangle measures 54 meters by 72 meters, what is the length, in meters, of the diagonal of the rectangle?Can someone explain this one?

Answers

Use the Pythagoras therom.
let the diagonal be x
⇒54²+72²=x²
⇒8100=x²
x=90meters

let the diagonal be a.
now, as we know that each angle in a rectangle is right angle.
thus we have a right angled triangle.
now, we can apply pythagoras theorum.
a^2 = 54^2 + 72^2
= 2916 + 5184
=8100
thus, a^2 = 8100
thus, a = 90.
Thus the diagonal is 90metres.

What is the slope-intercept form of an equation?
pls help me thanks

Answers

Answer:

It is the number before x.

Step-by-step explanation:

An example would be if some said to find the slope intercept form of 5/6x+3 the slope intercept form would be 5/6.

Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will last 10 years. The rules of the competition are simple. Each child can split up his or her $2000 into as many separate investments as they please. The children are encouraged to do their research on types of investments. The initial investments made may not be changed at any point during the 10 years; no money may be added and no money may be moved. Whichever child has made the most money after 10 years will be awarded an additional $10,000. Child Performance of investments over the course of the competition Albert $1000 earned 1.2% annual interest compounded monthly $500 lost 2% over the course of the 10 years $500 grew compounded continuously at rate of 0.8% annually Marie $1500 earned 1.4% annual interest compounded quarterly $500 gained 4% over the course of 10 years Hans $2000 grew compounded continuously at rate of 0.9% annually Max $1000 decreased in value exponentially at a rate of 0.5% annually $1000 earned 1.8% annual interest compounded biannually (twice a year) 1. What is the balance of Albert’s $2000 after 10 years? 2. What is the balance of Marie’s $2000 after 10 years? 3. What is the balance of Hans’ $2000 after 10 years? 4. What is the balance of Max’s $2000 after 10 years? 5. Who is $10,000 richer at the end of the competition?

Answers

The balance of Albert is $2159.07; the balance of Marie is $2244.99, the balance of Hans is $2188.35, and the balance of Max is $2147.40. Marie is $10,000 richer at the end of the competition.

What is Compound interest?

Compound interest is defined as interest paid on the original principal and the interest earned on the interest of the principal.

To determine the balance of Albert’s $2000 after 10 years :

If the amount of $1000 at 1.2 % compounded monthly,

A = P(1 +r/n)ⁿ n = 10 years

here P = $1000 and r = 1.2

A = 1000(1 + 0.001)¹²⁰

A = $1127.43

If Albert $500 losing 2%

So 0.98 × 500 = $490

If $500 compounded continuously at 0.8%

So A = P $e^(rt)$

A = 500 $e^(0.008* 10)$

A = 541.6

So the balance of Albert’s $2000 after 10 years :

Total balance = 1127.43 + 490.00+ 541.64 = $2159.07

To determine the balance of Marie’s $2000 after 10 years:

If 1500 at 1.4 % compounded quarterly,

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

If $500 Marie’s gaining 4 %

So 1.04 × 500 = $520.00

So the balance of Marie’s $2000 after 10 years

Total balance = 1724.99 + 520.00 = $2244.99

To determine the balance of Hans’ $2000 after 10 years:

If $2000 compounded continuously at 0.9%

So A = 2000 $e^(0.009* 10)$

A = $2188.3

To determine the balance of Max’s $2000 after 10 years :

If $1000 decreasing exponentially at 0.5 % annually

So A = 1000(1 - 0.005)¹⁰= $951.11

If $1000 at 1.8 % compounded bi-annually

So A = 1000(1 + 0.009)²⁰ = $1196.29

So the balance of Max’s $2000 after 10 years

Total balance = 951.11 + 1196.29 = $2147.40

Therefore, Marie is $10,000 richer at the end of the competition.

Learn more about Compound interest here :

brainly.com/question/25857212

#SPJ2

Answer:

Step-by-step explanation:

Albert:

$1000 earned 1.2% annual interest compounded monthly

= 1000 (1+.001)120

(periodic interest = .012/12 ,n is periods = 10yr x 12 mos)

$500 lost 2% over the course of the 10 years

= 500 (.98)

$500 grew compounded continuously at rate of 0.8% annually

= 500 e^008(10) 10 years interest .008 (in decimal form)

Add these three to see how Albert did with his investments

NEED HELP NOW!!!!!!!a 5 inch bamboo shoot doubles in height every 3 days. if the equation y=ab^x , where x is the number of doubling periods , represents the height of the bamboo shoot, what are the values of a and b?

Answers

Answer a = 5 and b = 2.

Procedure

Initially means x = 0, then

5 = a*b^0 = a*1 = a, then a = 5

When x = 1, the height is the double of 5, i.e 10 and

10 = a.b^1 = a.b ⇒ b = 10/a = 10/5 = 2

The a = 5 and b = 2, so the equation is y =5(2)^x

F(x)=6x+8 what is f(3)?

Answers

Answer:

Step-by-step explanation:

6(3) =18 18+8=26

F(x)=6x+8
F(3)=6(3)+8
F(3)=18+8
F(3)=26

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