Answer:
8.46 liters of 0.123 NaOH contains 25.0 grams of NaOH.
Explanation:
Molar is defined as Moles/Liter. 0.123 M means there is 0.123 moles of NaOH per 1 liter. We are asked to determine how many milliliters of this concentration NaOH it would take to deliver 25.0 grams of NaOH.
Use the units to guide the calculation.
Remember that: Concentration x Volume = Moles
(0.123 moles/liter)*(V) = moles
We want 25.0 grams of NaOH. Let's convert that to moles using the molar mass of NaOH:
(25.0 grams NaOH)/(24.0 g/mole) = 1.04 moles NaOH.
Now we can write:
(0.123 moles/liter)*(V) = 1.04 moles NaOH
V = (1.04/0.123) Liters
V = 8.46 liters
b. shape
c. size
d. shape and volume
At a constant temperature and pressure, liquids retain their volume of matter.
Matter is defined as total mass which occupy in space, all the physical structures are composed of matter, it can be present in three basic states such as solid, liquid, and gas.
The atoms are basic unit of matter and that make up the objects which can be visible and touched every day, the amount of matter in an object can be determined by its mass.
A physical property of matter is an independent of its chemical composition. Density, color, hardness, melting and boiling points, and electrical conductivity are the examples.
Some characteristics like density, color, mass, volume, length, malleability, melting point, hardness, odor, temperature are some properties of matter.
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Answer:
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is .
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 104 kPa
= final pressure of gas = 52 kPa
= initial volume of gas =
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is .
Answer:
a saturated hydrocarbon that has more than 35 carbons in its chain
Explanation: Alkanes with a chain length of approximately 35 or more carbon atoms are found in bitumen (asphalt), used (for example) in road surfacing. However, the higher alkanes have little value and are usually split into lower alkanes by cracking.
Three main approaches are available for observational research: controlled observations, naturalistic observations, and participant observations. The two categories of observation are qualitative and quantitative. The correct option is A.
The observation approach entails watching, either manually or mechanically, what people actually do or what happens when they buy or consume something. Information is gathered by watching processes in action. Observations might be either qualitative or quantitative. Scientists make both qualitative and quantitative observations to acquire knowledge.
Observations that describe something's "qualities" are referred to as qualitative observations. These wouldn't involve counting or measuring and would instead contain qualities like texture, color, and shape. Utilizing standard scales to count or measure is a requirement for quantitative observations.
Thus the correct option is A.
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The correct answer is:
qualitative and quantitative.
Explanation:
Observation is the rapid retrieval of information from a first source. In living beings, observation contracts the senses. In science, observation can also include the recording of data via the use of scientific tools. Qualitative observation is a personal process of collecting data or knowledge while quantitative observation is an objective process of accumulating data or information.
There are 929 grams in 1.11 moles of manganese sulfate.
The mole is a SI unit of measurement that is used to calculate the quantity of any substance.
Step1: Calculate the molar mass of
3(54.94) + 7(32.07) + 28(16) = 837.31g
Step2: Calculate the mass of
Thus, the mass of 1.11 moles of is 929 grams.
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Step 1: Find the molar mass of Mn3(SO4)7.
Mn3(SO4)7 = 3(54.94) + 7(32.07) + 28(16) = 837.31g
Step 2: Calculate grams of Mn3(SO4)7 in the following manner:
1.11 mol Mn3(SO4)7 (837.31g Mn3(SO4)7 /1 mol Mn3(SO4)7 ) = 929g Mn3(SO4)7