if the sides of a square are increased by 3m,the area becomes 64m2. find the length of a side of the original square

Answers

Answer 1

Answer: $a-the\ length\ of\ a\ side\ of\ the\ original\ sqare\n\n(a+3)^2=64\Rightarrow a+3=√(64)\n\na+3=8\n\na=8-3\n\na=5\ (m)\leftarrow solution$

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The equation y+6=1/3(x-9)is written in point-slope form. What is the equation written in slope-intercept form?

Answers

Answer:

y=1/3x-9

Step-by-step explanation:

y+6=1/3(x-9)

i.e y=1/3x -3-6

i.e, y=1/3x -9

it's in slope intercept form now,i.e, in form y=mx+c,where m is slope of st. line,here 1/3 is slope!

✌️:)

Answer:c

Step-by-step explanation:

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

Answers

Since point L is merely found on the line MN, ML and LN are considered to be line segments. So adding both line segments should add up to line MN's total length which is 31 units. We can use the given relations to create a mathematical equation as follows:

Given: MN = 31; ML = h - 15; LN = 2h - 8

MN = ML + LN

Substituting the given values:
31 = h - 15 + 2h - 8
31 = 3h - 23

It is necessary to solve for the value of h. To do this, we must isolate h and solve for it:

Adding 23 to both sides of the equation:
31 + 23 = 3h - 23 + 23
54 = 3h
h = 18

Substituting the value of h to the equation of LN we get the following:
LN = 2(18) - 8
LN = 36 - 8
LN = 28

Therefore the value of LN is 28.

Select the symbol = (equal to) or ≠ (not equal to) to make the expression true.{1, 2, 3, 4, 5} ? {whole numbers between 1 and 5 inclusive}

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I'm not sure whether '1 and 5 inclusive' means that both 1 and 5 are included or only 5.
If it's the former, then $\{1,2,3,4,5\}=\text{whole numbers between 1 and 5 inclusive}$

Answer:

the correct answer is not equal to or the crossed out equal sign

Step-by-step explanation:

Odyssey

I am not sure if this is right can someone check it ASAP please

Answers

Answer:

x=10

Step-by-step explanation:

3(4x-12) = 84

Divide each side by 3

3/3(4x-12) = 84/3

4x-12 =28

Add 12 to each side

4x-12+12 = 28+12

4x= 40

Divide each side by 4

4x/4 = 40/4

x = 10

If A ⊂ B, then A ∩ B = A ∪ B. always, sometimes, never

Answers

Answer:

Hence, the property:

A ∩ B = A ∪ B never hold .

Step-by-step explanation:

We are given that set A⊂B .

This means that set A is properly contained in set B.

i.e. A≠B

This means that there are some elements in set B which are not in set A.

Now we have to show whether the following property A∩B=A∪B

always, sometimes or never hold.

As A is a proper set of B.

This means that: A∩B=A ( Since A is a smaller set)

Also, A∪B=B (Since B is a bigger set)

Hence, A∩B ≠ A∪B (Since A≠ B)

The answer is never.

Mary Moneypenny went to her bank each week and opened a club account. She deposited $21.75 per time period. If she made 12 deposits before interest was credited, how much would she have deposited before interest was credited?The balance would be $ before interest was credited.

Answers

Answer:

$261

Step-by-step explanation:

We are given that Mary Moneypenny went to her bank each week and opened a club account.

She deposited money per time period=$21.75

She made total deposits before interest was credit=12

We have to find out total deposits money in her account before interest was credited.

We are multiplying number of deposits with deposit per time period to obtain the value of total deposits

She would have total deposit money before interest was credit= $12* 21.75$ =$261

Hence, the balance would be $ 261 before interest was credited.

$21.75 x 12 deposits = $261

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A box is sitting on the floor. The box was then pulled with a force, Ft. The box did not move. The free-body diagram of the box is shown.A free body diagram with 4 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = negative 20 N. The second vector is pointing right, labeled F Subscript t Baseline = 10 N. The third vector is pointing upward, labeled F Subscript N Baseline = 20 N. The fourth vector is pointing left, labeled F Subscript f Baseline = negative 10 N. The up and down vectors are the same length. The right and left vectors are the same length.Which describes the motion of the box based on the resulting free-body diagram?It is moving up with a net force of 20 N.It is moving to the right with a net force of 10 N.It is in dynamic equilibrium with a net force of 0 N.It is in static equilibrium with a net force of 0 N.Mark this and return