Answer:
Step-by-step explanation:
2. I think C
3.D
4.D
5.B
6. D
7.B
8.A
9.A I think
Answer:
It is miles far from Chester to Durbin.
Step-by-step explanation:
Given:
Its 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via barton and Chester, is 35 miles.
Now, to find the distance from Chester to durbin.
Distance from Alston to Barton =
Distance from Barton to Chester =
As, given the distance from Alston to Durbin, via barton and Chester, is 35 miles.
Thus, the total distance = 35 miles.
So, we add the distance of Alston to Barton and Barton to Chester and get the distance from Alston to Chester:
Distance from Alston to Chester
Now, to get the distance from Chester to durbin we subtract distance from Alston to Chester from the total distance:
Therefore, it is miles far from Chester to Durbin.
- 3y + 7 + 3(y-1) = 2(2y+6)
- (x-5)(x+4) = (x+7)(x-6)
- 2(x+1)2(x-2)2 = x(x-3)
To begin this problem, we need to use the two points that we are given to find the slope of the line. Slope is defined as the change in y values divided by the change in x values, or rise/run, and is represented by the variable m.
m = (y1-y2)/(x1-x2) = (8-0)/(3-6) = 8/(-3) = -8/3
Now, we can use the slope and one of the points from our given values to create an equation of the line in point-slope form.
y = m(x-h) + k, where a point on the line is (h,k)
y = -8/3(x - 3) + 8
Now, we can distribute our slope and simplify through addition.
y = -8/3x + 8 + 8
y = -8/3x + 16
Therefore, your answer is y = -8/3x + 16.
Hope this helps!