y > One-halfx + 1
On a coordinate plane, 2 straight lines are shown. The first solid line has a positive slope and goes through (negative 2, 0) and (0, 1). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 1, negative 3) and (0, 2). Everything to the right of the line is shaded.
(–1, 3)
(0, 2)
(1, 2)
(2, –1)
(2, 2)
The ordered pairs which make both the inequalities true are (1, 2).
Linear inequalities are defined as those expressions which are connected by inequality signs like >, <, ≤, ≥ and ≠ and the value of the exponent of the variable is 1.
Given two linear inequalities,
y < 5x + 2 and y > 1/2 x + 1
Consider y < 5x + 2.
(-1, 3) ⇒ 3 < -5 + 2 ⇒ 3 < -3, which is not true.
(0, 2) ⇒ 2 < 0 + 2 ⇒ 2 < 2, which is not true
(1, 2) ⇒ 2 < 5 + 2 ⇒ 2 < 7, which is true
(2, -1) ⇒ -1 < 10 + 2 ⇒ -1 < 12, which is true
(2, 2) ⇒ 2 < 10 + 2 ⇒ 2 < 12, which is true
Consider y > 1/2 x + 1.
Substitute the points which are true for first inequality in this one.
(1, 2) ⇒ 2 > 1/2 + 1 ⇒ 2 > 3/2, which is true
(2, -1) ⇒ -1 > 1 + 1 ⇒ -1 > 2, which is not true
(2, 2) ⇒ 2 > 1 + 1 ⇒ 2 > 2, which is not true.
Hence the point is (1, 2) which is true for both inequalities.
To learn more about Linear Inequalities, click on the link :
#SPJ2
Answer:
(0,2) and (1,2)
Step-by-step explanation:
• 6 green apple
• 10 orange
• 8 strawberry
One jellybean is randomly selected from the jar. After replacing the first jellybean, a second jellybean is randomly selected. Randomly selecting the second jellybean is -
f a dependent event because the outcome of the second jellybean
does not depend on the outcome of the first jellybean.
g an independent event because the outcome of the second jellybean
does not depend on the outcome of the first jellybean.
h an independent event because the outcome of the second jellybean
depends on the outcome of the first jellybean.
j a dependent event because the outcome of the second jellybean
depends on the outcome of the first jellybean.
There are 8 times 84s that are present in 672.
When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.
We need to find how many 84s are present in 672
We will simply divide the 84 by 672.
That is;
672/ 84
= 336/42
= 168/21
= 8
Hence, there are 8 times 84s that are present in 672.
Learn more about division here:
#SPJ2