Look at this set of ordered pairs: (16, 16) (7, 18) (19, 12) Is this relation a function? A. Yes B. No

Answers

Answer 1

Answer:

Answer:

The correct answer is A.

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Give one example of when you would use the friendly numbers strategy to subtract.

Answers

I would say: when we want to substract numbers that are close to each other, but when the respective digits of the number from which the second number is subtracted are lower than in the other number.

For example, when we want to substract 18 from 21. Those two numbers are very close, but if you did it digit by digit, your would run into a problem.

So instead you can collect their differences to the friendly number 20: 21 is one number away from 20, and 18 two numbers, which makes a total of 3 numbers: and 3 is the solution!

For this case, we use the strategy of friendly numbers when subtraction is something complex to do mentally.

Let's suppose that we have the following subtraction:

$117 - 83$

Using friendly numbers we have:

$(100 + 17) - (80 + 3)$

Then, applying the associative property we have:

$(100 - 80) + (17 - 3)$

Doing the calculations we have:

$20 + 14 = 34$

Finally we have:

$117 - 83 = 34$

The function f(x) = x2 – 9 is shifted 2 units up and 3 units to the left. Select the new function. A) g(x) = 2x2 – 6 B) g(x) = (x – 3)2 + 7 C) g(x) = 3x2 – 7 D) g(x) = (x + 3)2 – 7

Answers

We have the following function:
f (x) = x ^ 2 - 9
Applying the transformations we have:
Vertical translations
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
h (x) = x ^ 2 - 9 + 2
h (x) = x ^ 2 - 7
Horizontal translations
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
g (x) = (x + 3) ^ 2 - 7
Answer:
D) g (x) = (x + 3) ^ 2 - 7

What is the equation of the line that passes through (5, -2) and (-3, 4)?3x - 4y - 7 = 0
3x + 4y - 7 = 0
-3x + 4y - 7 = 0

Answers

Hello,
answer B

y+2=(4+2)/(-3-5)(x-5)
==>y+2=-3/4 (x-5)
==>4y=-3x+7
==>3x+4y-7=0

log6 (x+1)− log6 x =log6 29

Answers

$log_6(x+1)-log_6x=log_629;\ D:x+1 > 0\ \wedge\ x > 0\Rightarrow x\in\mathbb{R^+}\n\nlog_6(x+1)/(x)=log_629\iff(x+1)/(x)=29\n\n29x=x+1\n\n29x-x=1\n\n28x=1\ \ \ \ /:28\n\nx=(1)/(28)\in D\leftarrow solution$

$D:x+1>0 \wedge x>0\n D:x>-1 \wedge x>0\n D:x>0\n \log_6(x+1)-\log_6 x=\log_6 29\n \log_6(x+1)=\log_6 29+\log_6x\n \log_6(x+1)=\log_6 29x\n x+1=29x\n 28x=1\n x=(1)/(28)$

Look at the following picture. What would be the resultant vector of A+B? vector b is 4.78m 67 degress vector a 21 degrees 11.3mthe picture wont upload

Answers

Answer:

The resultant vector, A+B, has a Magnitude of 15.02 meters and an angle of 34.23 degrees

Step-by-step explanation:

We need to convert the vectors given to x,y coordinate form.

We use the formula below:

$x=ACos\theta$

$y=ASin\theta$

Where A is the magnitude and $\theta$ is the angle.

Vector A:

$x=ACos\theta\nx=(11.3)Cos(21)\nx=10.55$

and

$y=(11.3)Sin(21)\ny=4.05$

Vector B:

$x=(4.78)Cos(67)\nx=1.87$

and

$y=(4.78)Sin(67)\ny=4.40$

Now we can write the vectors as:

A = <10.55,4.05>

B = <1.87,4.40>

To add, A+B, we have:

A + B = <10.55+1.87, 4.05+4.40>

A + B = < 12.42, 8.45 >

To convert this into magnitude/degree format:

Magnitude = $√((12.42)^2 + (8.45)^2) =15.02$

Angle = $Tan^(-1)((8.45)/(12.42))=34.23$

if a number is a natural number, then it is also a whole number? what is the Inverse, the Converse, the Contrapositive, and the Bi-Conditional? and what is the Truth value for each one?

Answers

I believe you're learning geometry. Anyways, here are examples of natural numbers: 1, 2, 3... Meanwhile, here are examples of whole numbers: 0, 1, 2, 3... Natural numbers are all the positive whole numbers. Whole numbers are quantities that are both positive and neutral, and don't include any fractions or decimals.

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