Answer:
Part 1) The system of equations that represent this situation is equal to
b+p=42 and 5b+2p=144
Part 2) 20 binders were sold
Step-by-step explanation:
Let
b -----> the number of binders sold
p -----> the number of pencil pouches sold
Part 1)
we know that
The system of equations that represent this situation is equal to
b+p=42
5b+2p=144
Part 2) How many binders were sold?
we have
b+p=42
p=42-b ------> equation A
5b+2p=144 -----> equation B
substitute equation A in equation B
5b+2(42-b)=144
5b+84-2b=144
3b=144-84
3b=60
b=20 binders
Answer:
Step-by-step explanation:
the equation of a circle with a center at (0, 8) and a radius of 9.
To frame the equation of the circle we use center radius form of equation
Where (h,k) is the center and 'r' is the radius
Given center is (0,8) and radius = 9
h = 0 , k= 8 and r= 9
Plug in all the values
Answer:
73.00=5.50x+25.50y
Step-by-step explanation:
Answer:
25.50x + 5.50y = 73.00
Step-by-step explanation:
Pick a variable for x and y (x is pants and y is T-shirt)
Since she buys pants and T-shirts you add the two values
Since she spent $73 you make it equal to 73
Answer:
Option A
Step-by-step explanation:
System of the inequalities is,
y ≥ 2x
y < x + 4
By satisfying these inequalities with the points given in the options we can get the answer.
Option (A). (2, 5)
y ≥ 2x
5 ≥ 2(2)
5 ≥ 4
True.
y < x + 4
5 < 2 + 4
5 < 6
True
Therefore, Option (1) is the answer.
Option (B) (1, 6)
y ≥ 2x
6 ≥ 2(1)
6 ≥ 2
True.
y < x + 4
6 < 1 + 4
6 < 5
False.
Therefore, it's not the solution.
Option (C) (2, 3)
y ≥ 2x
3 ≥ 2(2)
3 ≥ 4
False.
y < x + 4
4 < 2 + 4
4 < 6
True.
Therefore, It's not the solution.
Option (D) (1, 5)
y ≥ 2x
5 ≥ 2(1)
5 ≥ 4
True.
y < x + 4
5 < 1 + 4
5 < 5
False.
Therefore, It's not the solution.
The additional information required to prove that the triangles are congruent using the ASAcongruence theorem is; ∠LNO ≅ ∠LNM
△LON and △LMN share a common side LN.
This means that for both triangles LN = LN by reflexive property as LN is congruent to itself.
∠OLN and ∠NLM are congruent.
We can see that L is an included angle of the congruent side LN.
We already have for L, and so the remaining angles that will make△LON and △LMN congruent are;∠LNO and ∠LNM.
Read more on ASA Congruence at; brainly.com/question/3168048
Answer:
The answer is ""
Step-by-step explanation:
Two angles will be congruent to each other in order to show ASA congruence between all the triangles. Its angle is a common angle in both triangles As a result, we'll use the ASA congruence law to show that perhaps the triangles are congruent.