CHEMISTRY HIGH SCHOOL

Determine the number of atoms in 25.0 grams of bromine, Br. (The mass of one mole of bromine is 79.90 g.)

Answers

Answer 1

Answer:

Answer: 1,88×10²³ atoms of Br in 25g of Br

Explanation:

25g Br

1 mol of Br =79,9g Br

Number of Avogadro: 6,022×10²³ = 1 mol

25gBr× 1molBr/79,9gBr =

6,022×10²³ atoms of Br/1 mol Br =

1,88×10²³ atoms of Bromine

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according to the third law if a football player hits another player with an action force of 1500n how much will the reaction force be

Answers

Answer:

The reaction would be 1500n (equal reaction)

Explanation:

This can be explained by Newton's third law of motion which states that for every action (force), there is an opposite and equal reaction. In other words, when two objects or people come in contact, the magnitude of force which they exert on each other is equal and they both feel an equal reaction force.

It doesn't matter whether one of the colliding bodies is of bigger mass than the other. This Newton's third law of motion is also known as the law of action and reaction.

Which of the following is a property of a metal? Low melting point

Permeability

Ductility

Not able to conduct heat

Answers

The correct answer is the 3rd option Ductility is a property of a metal. It is the ability of a material to deform under tensile stress.It is characterized by the ability to be stretched into wire-like form which is an ability of metals.

Atomic emission spectra are produced when the light emitted by an element passes through a prism. Which of the following statements is true regarding these spectra?A. All elements produce the same atomic spectra.
B. Elements produce continuous spectra.
C. Elements produce spectra with only a few distinct lines.

Answers

Option C: elements produce spectra with only few distinct lines.

The spectra are not continuos and are different for every element. This permits to identify elements.

Final answer:

Atomic emission spectra are unique to each element and consist of distinct lines representing different energy levels.

Explanation:

The correct statement regarding atomic emission spectra is option C: Elements produce spectra with only a few distinct lines.

The spectra produced by different elements are unique to each element, meaning that they have distinct patterns of lines.
These lines represent the different energy levels that electrons can occupy within the atom.
The specific pattern of lines in an atomic emission spectrum can be used to identify the element present in a sample of unknown composition.

Learn more about Atomic emission spectra here:

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Based on enthalpy of formation data species ∆H◦ f H2S(g) −20.63 kJ/mol O2(g) 0 kJ/mol H2O(ℓ) −285.83 kJ/mol SO2(g) −296.83 kJ/mol calculate ∆Hrxn for 2 H2O(ℓ) + 2 SO2(g) ←→ 2 H2S(g) + 3 O2(g) 1. 562 kJ · mol−1 2. −562 kJ · mol−1 3. −1124 kJ · mol−1 4. 1124 kJ · mol−1

Answers

Answer: The enthalpy change of the reaction is 1124 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_(rxn)=\sum [n* \Delta H^o_f_{\text{(product)}}]-\sum [n* \Delta H^o_f_{\text{(reactant)}}]$

For the given chemical reaction:

$2H_2O(l)+2SO_2(g)\rightarrow 2H_2S(g)+3O_2(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_(rxn)=[(2* \Delta H^o_f_((H_2S(g))))+(3* \Delta H^o_f_((O_2(g))))]-[(2* \Delta H^o_f_((H_2O(l))))+(2* \Delta H^o_f_((SO_2(g))))]$

We are given:

$\Delta H^o_f_((H_2O(l)))=-285.83kJ/mol\n\Delta H^o_f_((O_2(g)))=0kJ/mol\n\Delta H^o_f_((SO_2(g)))=-296.83kJ/mol\n\Delta H^o_f_((H_2S(g)))=-20.63kJ/mol$

Putting values in above equation, we get:

$\Delta H_(rxn)=[(2* (-20.63))+(3* (0))]-[(2* (-285.83))+(2* (-296.83))]\n\n\Delta H_(rxn)=1124kJ$

Hence, the enthalpy change of the reaction is 1124 kJ

Using less water is one way to practice watera. filtration.
b. distribution.
c. conservation.
d. irrigation.

Answers

Answer: Option (c) is the correct answer.

Explanation:

When we avoid wastage of water or overuse of then then it is known as conservation of water.

For example, turning off tap when bucket placed below it is filled with water means avoiding wastage of water.

Whereas over flow of water from the bucket is wastage of water.

Thus, we can conclude that using less water is one way to practice water conservation.

Using less water is one way to practice c. conservation. That would come in handy for a drought :D. Hope this helps and have a good day!

On a mission to a newly discovered planet, an astronaut finds gallium abundances of 61.29% for 69Ga and 39.71% for 71Ga . What is the atomic mass of gallium for this location?The mass of 69Ga is 68.7200amu . The mass of 71Ga is 70.9200amu .

Answers

To solve this, we multiply the each mass of the isotope by the percentage of abundance of each isotope.

average molecular weight = 0.6129(68.72amu) + 0.3971(70.92) = 70.28 amu

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