1-Propanol is combusted to provide heat. The equation and the enthalpy change for the process are shown below. C₃H₇OH(l)+4.5O₂( g)→3CO₂( g)+4H₂O(l)ΔH=−2,021 kJ Below is a list of sentences that describe a chemical process. Choose all of the sentences that apply to the above rea Check all that apply. a This process is exothermic. b The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is 2,021 kJ c The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is −4,042 kJ d The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is −2,021 kJ e This chemical process transfers heat from the surroundings to the system. f The enthalpy change for 2C₃H₇OH(l)+9O₂( g)→6CO₂( g)+8H₂O(l) is 4,042 kJ g This process is endothermic. h This chemical process transfers heat from the system to the surroundings.

Answers

Answer 1

Answer:

Explanation:

Let's analyze the statements one by one:

a) This process is exothermic.

True. The negative enthalpy change (-2,021 kJ) indicates that heat is released during the reaction, making it exothermic.

b) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 2,021 kJ.

False. The balanced chemical equation and enthalpy change given are for the combustion of 1 mole of propanol, not 2 moles.

c) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -4,042 kJ.

False. This statement suggests a doubled enthalpy change value in the wrong direction. The correct direction is negative (exothermic), but the magnitude is not doubled.

d) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -2,021 kJ.

False. This statement suggests the correct direction but doubles the magnitude. The correct magnitude is -2,021 kJ for 1 mole of propanol.

e) This chemical process transfers heat from the surroundings to the system.

False. The process is exothermic, which means it releases heat from the system to the surroundings.

f) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 4,042 kJ.

False. This statement suggests the correct magnitude but in the wrong direction. The correct direction is negative (exothermic).

g) This process is endothermic.

False. The process is exothermic, as indicated by the negative enthalpy change.

h) This chemical process transfers heat from the system to the surroundings.

True. An exothermic process like this releases heat from the system to the surroundings.

So, the correct statements are:

a) This process is exothermic.

e) This chemical process transfers heat from the surroundings to the system.

h) This chemical process transfers heat from the system to the surroundings.

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The half-life of cobalt-60 is 5.3 years. after __________ years, 1/4 of the original amount of cobalt-60 will remain.

Answers

The number of years required for 1/4 cobalt-60 to remain after decay is calculated as follows

after one half life 1/2 of the original mass isotope remains

after another half life 1/4 mass of original mass remains

therefore if one half life is 5.3 years then the years required

= 2 x 5.3years = 10.6 years

Answer:

10.6

Explanation:APEX

hydrogen is found primarily as two isotopes in nature: (1.0078u) and (2.0140u). Caluclate the percentage abundance of each isotope based on hydrogens average atomic mass

Answers

hydrogens average atomic mass = 1,01u

x = isotope about mass (1.0078u)
y = isotope about mass (2.0140u)

x + y = 100%
so:
x = 100% - y

$hydrogens ~average~atomic~mass=((1.0078\cdot x)+(2.0140\cdot y))/(100)\n 1.01=((1.0078\cdot (100-y))+(2.0140y))/(100)||\cdot 100\n 101=100.78-1.0078y+2.0140\n 101-100.78=1.0062y\n 0,22=1.0062y||:1.0062\n 0.219\%=y\n\n x=100\%-y\n x=100\%-0.219\%\n x=99.781\%\n\n$

answer:
$x=99.781\%\n y=0.219\%$

Which of the following factors renders a species more susceptible to disease and infertility?

Answers

The correct answer is this one: "B. inbreeding." Inbreeding renders a species more susceptible to disease and infertility. On the other hand, Large genetic diversity tends to be perceived as beneficial so that a single disease does not wipe out a species.

Here are the choices
A. Large genetic diversity
B. inbreeding
C. crossbreeding
D. recessive traits

Answer:

inbreeding

Explanation:

List one extensive and intensive
property of marker ink

Answers

Explanation:

Intensive property: It is the property of substance which is independent of quantity of substance. Color of an ink is an intensive property.

Extensive property: It is the property of substance which depends upon quantity of substance which is just opposite to intensive property. Volume of an ink is an extensive property.

volume is an extensive property of a marker ink and color is an intensive property of a marker ink.

Enter the molecular formula for butane, C4H10.
express in a chemical formula

Answers

Answer: the molecular formula is C₄H₁₀

You can also express it as: CH₃ - CH₂ - CH₂ - CH₃.

Explanation:

1) The molecular formula is the chemical formula for a covalent compound. It shows the elements present in one molecule of the compound: type of atoms and the number of each.

The number of each type of atoms is indicated by the subscript to the right of the symbol.

2) Butane is the alkane with 4 carbon atoms.

3) The general formula for the alkanes is CₓH₂ₓ₊₂, meaning thar for x atoms of C there are 2x+2 atoms of H. Therefore, for 4 C atoms there are 2(4)+2 = 8 + 2 = 10 H atoms.

That is why the molecular formula of butane is C₄H₁₀, meaning that each molecule of this alkane has 4 atoms of carbon and 10 atoms of hydrogen.

The other expression: CH₃ - CH₂ - CH₂ - CH₃, shows that this compounds is a chain, in which each C has 4 bonds, one with other C atom to the right, one with other C atom to the right and the difference (2 or 3) with H atoms.

The molecular formula of butane is $\boxed{{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}$ .

Further explanation:

The molecular formula is a chemical formula that depicts the total number and kinds of atoms present in a molecule. For example, molecular formula of carbon dioxide is ${\text{C}}{{\text{O}}_2}$ .

Hydrocarbon is a term for the organic compounds that consist of hydrogen and carbon only.

Types of hydrocarbons:

1. Saturated hydrocarbons

The simplest hydrocarbons that are composed of only single bonds are called saturated hydrocarbons. These hydrocarbons have the general formula of ${{\text{C}}_n}{{\text{H}}_(2n + 2)}$ , where n is the number of carbon atoms. These hydrocarbons have suffix “ane” in their names. Examples of such hydrocarbons are methane, hexane, and propane.

2. Unsaturated hydrocarbons

These have one or more multiple bonds in them. These hydrocarbons have suffix “ene” or “yne”, depending on whether there is a double or triple bond between them. Hydrocarbons comprising of double bonds are called alkenes and those having triple bonds are called alkynes.

The name of butane includes the suffix “ane”. This implies it is a saturated hydrocarbon and contains only single bonds in it. The prefix “but” indicates the presence of four carbon atoms in this molecule.

Substitute 4 for n in the general formula of alkane $\left( {{{\text{C}}_n}{{\text{H}}_(2n + 2)}} \right)$ to find out the formula of butane.

$\begin{aligned}{\text{Molecular formula of butane}} &= {{\text{C}}_{\text{4}}}{{\text{H}}_{\left( {{\text{2}}\left( {\text{4}} \right){\text{ + 2}}} \right)}}\n&= {{\text{C}}_4}{{\text{H}}_(10)}\n\end{aligned}$

Learn more:

Calculate the moles of ions in the solution: brainly.com/question/5950133
Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Stoichiometry of formulas and equations

Keywords: molecular formula, butane, C4H10, 4, ane, ene, yne, alkane, alkyne, alkene, saturated hydrocarbon, unsaturated hydrocarbon.

What part of the atom is responsible for the behavior of the alpha particles?

Answers

Answer:

nucleus

Alpha particles are subatomic fragments consisting of two neutrons and two protons. Alpha radiation occurs when the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low) and alpha particles are emitted to restore balance.

Explanation:

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Find the final equilibrium temperature when 15.0 g of milk at 13.0 degrees c is added to 148 g of coffee with a temperature of 88.3 degreesc. assume the specific heats of coffee and milk are the same as for water (c = 4.19 j/g•c), and disregard the heat capacity of the container.

A sealed container has 1 mole of helium and 2 moles of nitrogen at 30DC when the total pressure of mixture is 0.60 atm what is the partial pressure of the nitrogen?