Which net change occurs in a nuclear fusionreaction?
(1) Ionic bonds are broken.
(2) Ionic bonds are formed.
(3) Energy is converted to mass.
(4) Mass is converted to energy.

Answers

Answer 1

Answer: The correct answer would be option 4. Fusion reaction is a type of nuclear reaction where two or more nuclei combine or collide to form an element with a higher atomic number. This happens when the collision is in a very high speed. In this process, some of the matter of the fusing nuclei is converted to energy.

Related Questions

Reaction isCO2(g) + C(s) <=> 2CO(g) Kp = 5.7, 1200KCalcualte the total pressure at equilibrium when 4.45g CO2 is introduced into a 10.0L container and heated to 1200K in the presence of 2.00g of graphite
The atom in a sample of an element must contain nuclei with the same number of?
The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
These two compounds are in the liquid phase at 293 K a. Br₂ and Hg b. Cl2 and F2 c. NH4^{+} and H₃O^{+} d. Fe and Co e. Diamond and graphite
The discoverer of the electron was: Faraday Thomson Henry Millikan

How many primary oxygen systems are there? One Five Three Ten

Answers

The answer is three.
There are three type types of oxygen therapy system. The Compressed Oxygen Cylinders or commonly known as green tanks, the Oxygen Concentrators, and the Liquid Oxygen Systems. The type of oxygen system you need varies on the amount oxygen you need.

Which of the following is true of group 6A?Includes Chlorine

Includes Sulfur

Gain 2 electrons

Tend to form +2 ions

Have 5 valence electrons

Answers

Answer:

The answer to your question is: Includes sulfur and gain two electrons

Explanation:

Includes Chlorine This option is wrong, Chlorine belongs to group VII.

Includes Sulfur This option is true, Group VI includes Oxygen, Sulfur, Selenium, Tellurium.

Gain 2 electrons. This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.

Tend to form +2 ions This option is wrong, this elements form -2 ions

Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.

what would be the final volume when 2.20 M solution is made from 25.0 mL of a 12.0 M solution? plzz show work

Answers

Answer:

136.36 mL

Explanation:

Here we have to use the dilution formula

From C1V1= C2V2

Where;

C1= initial concentration of the solution= 12.0 M

C2= final concentration of the solution= 2.20 M

V1 = initial volume of the solution= 25.0 ml

V2= final volume of the solution= ?????

Then recall;

C1V1=C2V2

V2 = C1V1/C2

Substituting values from the parameters given;

V2= 12.0 × 25.0 / 2.20

V2= 136.36 mL

Which compound has the strongest hydrogen bonding between its molecules? 1. HBr 2. HF 3. HCl 4. HI

Answers

You can compare the strength of the hydrogen bonding by comparing the electronegativities of the other elements. All the four elements, Br, F, Cl and I belong to the same group in the periodic table: group 17 named halogens. Then the kind of bonding they form is similar: polar covalent. You must know the trend of the electronegativities in the periodic table. Electronegativity decrease when you down across a group. Then the electronegativity of F is the higher of the group (indeed, it is the highest of all the 118 elements) . The higher the electronegativity the stronger the attraction that the halogen attracts the electrons and the stronger the hydorgen bonding. Then, the conclusion is that HF has the strongest hydrogen bonding.

The correct answer is HF

What fraction of a Sr-90 sample remains unchanged after 87.3 years

Answers

The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^(n) = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_(1/2) = (t)/(n)$
where:
$t_(1/2)$ - half-life
t - total time elapsed
n - a number of half-lives

The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
$t_(1/2)$ = 28.8 years

We need:
n = ?
x = ?

We could first use the second equation, to calculate n:
If:
$t_(1/2) = (t)/(n)$ ,
Then:
$n = (t)/( t_(1/2) )$
⇒ $n = (87.3 years)/(28.8 years)$
⇒ $n=3.03$
⇒ n ≈ 3

Now we can use the first equation to calculate the remained amount of the sample.
$(1/2)^(n) = x$
⇒ $x=(1/2)^3$
⇒ $x= (1)/(8)$

How do you find the volume occupied by 454 grams of copper if the density equals 8.92 g/mL?

Answers

V=M/P
M=454g
p=8.92
v=50.896860986
3 significant figures
v= 50.9

Final answer:

The volume occupied by 454 grams of copper, given a density of 8.92g/mL, can be calculated using the formula for density (Density = Mass / Volume). When rearranged to find volume (Volume = Mass / Density) and substituting the given values, the volume occupied is approximately 50.9 mL.

Explanation:

When calculating volume in chemistry, we use the formula for density, which is: Density = Mass / Volume. In this case, the given values are mass (454g) and density (8.92g/mL). If we rearrange the formula to solve the volume, we get: Volume = Mass / Density. So, if we substitute the given values into the equation, we obtain: Volume = 454g / 8.92g/mL. In performing the operation, we get approximately 50.9 mL. Hence 454 grams of copper occupy 50.9 mL of volume.