Find the length between (7,-6) (5,-10)

Answers

Answer 1
Answer:

Answer;

The exact length is 2√5 units. You can also use a calculator to get an approximate value, which is about 4.47 units


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1/3 :4= x/6
Please solve!

Answers

Answer:

1/2

Step-by-step explanation:

1/3÷4=x/6

First divide 1/3÷4 to get 1/12

then multiply both sides by 12 to get 2x=1

Hence, x=1/2

Please help, I don't know the answer!

Answers

Answer:

C. 6*9^3 + 1*9^2 + 1*9^1 + 5*9^0

Step-by-step explanation:

In base 9, each digit to the left represents a power of 9.

The rightmost digit represents 9^0, the next digit to the left represents 9^1, the next digit to the left represents 9^2, and the 4th digit represents 9^3.

Answer: C. 6*9^3 + 1*9^2 + 1*9^1 + 5*9^0

Solve 5m − 3h = 45 for h. Show your work.

Answers

Answer:

h =  -15 +(5)/(3).

Step-by-step explanation:

Given  :  5m − 3h = 45.

To find : Solve  for h.

Solution : We have given 5m − 3h = 45.

On subtracting both sides by 5m.

- 3h = 45 - 5m.

On dividing both sides by -3 .

h = (45 - 5m)/(-3).

h = (45)/(-3) +(5)/(3).

h =  -15 +(5)/(3).

Therefore , h =  -15 +(5)/(3).

5m-3h= 45
-5m -5m
(-3h= 45-5m)/(-3) to get h alone.
h= (-45/3)-(5/-3)m, simplify
h=-15+(5/3)m

What’s the y value for the given value of x Y=x+5; x=3

Answers

Answer:

y=8/3

Step-by-step explanation:

pictomath lol

What is the PE of a 10 kg box that drops 10 meters?

Answers

Change of PE over a height of 10m = M G H = (10) (9.8) (10) = 980 joules.

When the box hits the bottom, it has 980 joules less PE than it had
before it started dropping. 

(As well as 980 joules more kinetic energy.)
P.E = mgh                           
M= MASS
G= ACCELERATION DUE TO GRAVITY
H = HEIGHT
P.E= 10 * 10 * 10
P.E = 1000J

6. What are the solutions to(x + 3)2 = 49

x= -2 and x = -16
x = 2 and x = V-10
x = 4 and x = -10
x = 40 and x = -58

Answers

Answer:

The answer is x=4 or x=−10

Solutions:

(x + 3)² = 49

(x+3)(x+3)=49

x²+6x+9=49

x²+6x+9-49=0

(x-4)(x+10)

x-4=0 x+10=0

x=4 x=-10