MATHEMATICS HIGH SCHOOL

I need help with that

Answers

Answer 1

Answer:

x intercept = (3,0)

y intercept = (0, -2)

Step-by-step explanation:

x-intercept:

2x = 3y +6

x intercept = 6/2 = 3

y-intercept

-3y = -2x + 6

y = 2/3x - 6/3

y = 2/3 - 2

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The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.

Answers

So,

The problem tells us that the length of the rectangle is 5 feet more than twice the width.
Mathematically:
length = 5 + 2width
l = 5 + 2w

We know that the perimeter is 2l + 2w.
2l + 2w = 130

2(5 + 2w) + 2w = 130

Distribute
10 + 4w + 2w = 130

Collect Like Terms
10 + 6w = 130

Subtract 10 from both sides
6w = 120

Divide both sides by 6
w = 20

The width is 20.

Since
l = 5 + 2w

Substitute
l = 5 + 2(20)

Multiply
l = 5 + 40

Collect Like Terms
l = 45

The length is 45.

Check
2l + 2w = 130

2(45) + 2(20) = 130

90 + 40 = 130

130 = 130

Width: 20 ft.
Length: 45 ft.

The price of a pair of shoes is $45.90. The sales-tax rate is 5 percent. How much sales tax do you need to pay?a)0.30 b)2.30 c)23 d)48.20

Answers

45.90*0.05=2.295.The answer is $2.30 when you round it off.

In nathan's baseball card collection, 58% of the cards are players from the national league. he has 702 baseball cards. about how many baseball cards are playears from the national league?

Answers

About 407 cards are from the national league.

Find the next two terms in the following sequence.

13, -5, -35, -77,...

Answers

$13;-5;-35;-77;...\n\na_n=19-6n^2\n\na_1=19-6\cdot1^2=19-6=13\n\na_2=19-6\cdot2^2=19-6\cdot4=19-24=-5\n\na_3=19-6\cdot3^2=19-6\cdot9=19-54=-35\n\na_4=19-6\cdot4^2=19-6\cdot16=19-96=-77\n\na_5=19-6\cdot5^2=19-6\cdot25=19-150=-131\n\na_6=19-6\cdot6^2=19-6\cdot36=19-216=-197$

I really need help, thanks.

Answers

Hello,
I suppose the function is y=3√(6x+42)

==>6x+42>=0 (it must be a square root of a positive)
==>6x>=-42
==>x>=-42/6
==>x>=-7

ANSWER D

What are the solutions to the equation (x – 2)(x + 5) = 0?

Answers

A product of two (or more) factor can be zero if and only if at least one of the factors is zero.

In other words, you cannot multiply two non-zero real numbers, and have zero as a result.

So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

$x-2 = 0 \iff x=2$

The second factor is zero if

$x+5 = 0 \iff x=-5$

The solutions to the equation are x = 2 and x = -5.

To find the solutions to the equation (x – 2)(x + 5) = 0, you need to set each factor equal to zero and solve for x. When the product of two factors is equal to zero, one or both of the factors must be equal to zero.

Set x - 2 = 0 and solve for x:

x - 2 = 0

x = 2

Set x + 5 = 0 and solve for x:

x + 5 = 0

x = -5

The solutions to the equation are x = 2 and x = -5. When you substitute these values back into the original equation, you get (2 - 2)(2 + 5) = 0 and (-5 - 2)(-5 + 5) = 0, both of which evaluate to 0, confirming that these are indeed the solutions.

To know more about equation:

brainly.com/question/10724260

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