What is the main reason that people are hesitant to use nuclear energy a. It produces radioactive waste. b. It uses large amounts of water. c. The ore used for nuclear energy must be mined. d. It is more damaging to natural habitats than the use of coal.

Answers

Answer 1

Answer: Nuclear energy is FEARED due to production of radioactive waste. Expose to radioactive waste have already taken place like Fu.kushima nuclear power station (March 2011) and more famously known; Chernobyl (April 1986). Nuclear waste is dangerous for over tens of thousands of years! For humans, radioactive waste breaks up our DNA. Either damaging our cells, or MUTATING them, which eventually lead to cancer and ever death.

Answer 2

Answer:

The main reason that people are hesitant to use nuclear energy is It is more damaging to natural habitats than the use of coal.

What is nuclear energy?

Nuclear energy refers to the energy that is obtained from the nucleus of an atom. It is the energy that that can be obtained from a fusion or a fission reaction.

However, there are many uncertainties that surround the use of nuclear energy especially the posibility of a nuclear disaster. Hence, the main reason that people are hesitant to use nuclear energy is It is more damaging to natural habitats than the use of coal.

Learn more about nuclear energy: brainly.com/question/3385510?

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PLEASE HURRY IM BEING TIMED

Answers

Answer: -3

Step-by-step explanation: I GOT YOU BRO

AB+C=50
BC+A=41
What is A, B, C

Answers

For the given system of equations, when B = 2, the values are A = 133 and C = -216. Values will vary with different choices of B.

To solve for the values of A, B, and C in the system of equations:

AB + C = 50

BC + A = 41

We can use a systematic approach. Let's first isolate one variable in one equation and then substitute it into the other equation.

From the first equation (AB + C = 50), we can isolate C:

C = 50 - AB

Now, substitute this expression for C into the second equation:

B(50 - AB) + A = 41

Expand and simplify:

50B - $AB^2$ + A = 41

Rearrange terms:

$AB^2$ - 50B + A = 41

Now, let's consider this as a quadratic equation in terms of A and solve for A:

A = 41 - $AB^2$ + 50B

Now that we have expressions for A and C in terms of B, we can choose a value for B, and then calculate the corresponding values of A and C. For instance, let's say B = 2:

A = 41 - (2)( $2^2$ ) + 50(2) = 41 - 8 + 100 = 133

C = 50 - (2)(133) = 50 - 266 = -216

So, for B = 2, we have A = 133 and C = -216. You can similarly calculate values for different values of B.

For more such questions on equations

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Complete question below:

What are the values of A, B, and C in the system of equations:

AB + C = 50

BC + A = 41?

A=4
B=3
C=7

43+7=50
37+4=41

Simplify the expression: 3x + 5 + 7x=

Answers

The answer would be 10x + 5

Hello!

The answer is 10x + 5!

Hopefully this helps! <3 ^^

Is this graph a function

Answers

Answer:

To determine if a graph is a function, we need to check if each input (x-value) has a unique output (y-value). We can do this by performing the vertical line test.

Here's how you can determine if a graph is a function using the vertical line test:

1. Imagine drawing a vertical line anywhere on the graph.

2. If the vertical line intersects the graph at more than one point, then the graph is not a function.

3. However, if the vertical line intersects the graph at only one point, then the graph is a function.

So, if you have a specific graph in mind, you can visualize drawing vertical lines and see if they intersect the graph at more than one point. If they do, then the graph is not a function. If each vertical line intersects the graph at only one point, then the graph is a function.

Step-by-step explanation:

You are wanting to simulate tossing a coin 20 times to determine the probability of getting tails. Starting with the first row, you use the list of random numbers shown to do so, letting 0-4 represent heads and 5-9 represent tails. What is the probability the coin lands on tails?

Answers

When you flip a fair coin, there is always a 50% chance of heads, and a 50% chance of tails. Not sure the rest of info is relevant here

Final answer:

Simulated coin tossing uses random numbers, where 0-4 and 5-9 represent heads and tails respectively. The theoretical probability of getting tails is 0.5, but empirical probabilities can differ. This discrepancy, assumed to reduce with more trials, is accounted for by the Law of Large Numbers.

Explanation:

In the context of the provided problem, you are attempting to simulate tossing a coin 20 times using a system of random numbers, where you've assigned 0-4 to represent heads and 5-9 to represent tails. Theoretically, in a fair coin toss, there's a 50% chance (0.5 probability) of getting either heads or tails.

However, experimental or empirical probability may not always align with this theoretical likelihood, especially in smaller samples. This discrepancy is due to randomness and doesn't necessarily imply the coin or system is biased. Over many trials, the relative frequency of getting tails should approach the theoretical probability, according to the law of large numbers.

To calculate the empirical probability of getting tails in your simulation, you would tally up the total number of 'tails' results (numbers 5-9) from your 20 trials, then divide that count by the total number of trials (20). So, if you get 12 'tails' results, your empirical probability would be 12/20 = 0.6.