Look at this equation k + 31 = 72 Which related equation below will correctly solve for the variable k? Question 1 options: k = 72 + 31 k = 72 - 31 k = 72 · 31 k = 72 ÷ 31

Answers

Answer 1

Answer:

Answer:

To solve for the variable "k" in the equation "k + 31 = 72," you need to isolate "k" on one side of the equation. Here's how you can do it using friendly words and reasons:

1. Start with the original equation: "k + 31 = 72."

2. To isolate "k," you want to get rid of the "31" on the left side of the equation. You can do this by subtracting 31 from both sides to keep the equation balanced.

3. Subtract 31 from both sides:

"k + 31 - 31 = 72 - 31."

4. Simplify both sides:

"k = 41."

Step-by-step explanation:

So, the correct equation to solve for the variable "k" is: "k = 72 - 31," and this will give you the value of k, which is 41.

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Answers

$m\angle ADC=m\angle ADB+m\angle BDC\n\nm\angle ADC=112^o,\ m\angle ADB=6x+7,\ m\angle BDC=12x-3\n\n\text{substitute}\n\n(6x+7)+(12x-3)=112\n\n(6x+12x)+(7-3)=112\n\n18x+4=112\ \ \ \ |-4\n\n18x=108\ \ \ \ |:18\n\nx=6\n\nm\angle ADB=6x+7\to m\angle ADB=(6(6)+7)^o=(36+7)^o=43^o$

What value of x makes the equation true?–4.9 = –5.7 + x
a. x = –10.6
b. x = –0.8
c. x = 0.8
d. x = 10.6

Answers

-4.9=-5.7+0.8
-4.9=-4.9
Answer is C

Exponential Form3.log 1/4 1=0
4.log 1/2 32= -5
Evaluate the logarithm
6. log27 3=
8. log 1/4 256=
9. log 10 .001=
10. log 64 2=

Answers

6. 1/3
8. -4
9. -3
10. 1/6

loga n=z ⇔a^z=n

Therefore:
3)log 1/4 1=0 ⇔(1/4)⁰=1
4)log 1/2 32 -5 ⇔(1/2)⁻⁵=2⁵=32

6)
log 27 3=n ⇔ 27^n=3
27=3³
(3³)^n=3 ⇒n=1/3 (3³)¹/³=3³/³=3¹=3

Answer: log 27 3=1/3

7)
log1/4 256=n ⇔(1/4)^n=256
256=2⁸=4⁴
(1/4)^n=4⁴ ⇒n=-4 [ (1/4)⁻⁴=4⁴=256 ]

Answer: log1/4 256=-4

9)
log 10 0.001=n ⇔ 10^n=0.001
0.001=10⁻³
10^n=10⁻³ ⇒n=-3

answer: log 10 0.001=-3

10)
log 64 2=n ⇔64^n=2
64=2⁶
(2⁶)^n=2 ⇒2(⁶n)=2¹ ⇒ 6n=1 ⇒ n=1/6

answer: log 64 2= 1/6

To best estimate the quotient in scientific notation. what number should replace m?6.33x 10

1.79x 103

3 x 10"