The test scores of a geometry class are given below.90, 75, 72, 88, 85

The teacher wants to find the variance for the class population. What is the value of the numerator of the calculation of the variance?

Answers

Answer 1
Answer: Variance is given by s^2 = [summation (x - mean)^2] / n.
mean = (90 + 75 + 72 + 88 + 85) / 5 = 82
Variance = [(90 - 82)^2 + (75 - 82)^2 + (72 - 82)^2 + (88 - 82)^2 + (85 - 82)] / 5
= [8^2 + (-7)^2 + (-10)^2 + 6^2 + 3^2] / 5
= (64 + 49 + 100 + 36 + 9] / 5
= 258 / 5
Therefore, the value of the numerator of the calculation of the variance of the data set is 258.
Answer 2
Answer:

Answer: data set is *258*

Step-by-step explanation:

Too goo


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Answers

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3 12 Find the nth term of each sequence. (a) -1, -3, -5, -7, -9, .​

Answers

Hello!

Answer:

\Large \boxed{\sf -11}

Step-by-step explanation:

→ We want to find the next term of this sequence:

\sf (-1, -3, -5, -7, -9, ...)

→ The sequence (-1, -3, -5, -7, -9, ...) is an arithmetic sequence because the difference between any two consecutive terms is constant.

→ The common difference is -2.

→ So the next term of this sequence is equal to:

\sf -9-2 = \boxed{\sf -11}

Conclusion:

The next term of the sequence (-1, -3, -5, -7, -9, ...) is -11.

Solve with quadratic formula 8x^2-9x-5=0

Answers

8x^(2) - 9x - 5 = 0

x = \frac{-(-9) +/- \sqrt{(-9)^(2) - 4(8)(-5)}}{2(8)}

x = (9 +/- √(81 + 160))/(16)

x = (9 +/- √(241))/(16)

x = (9 +/- 15.524)/(16)

x = 0.5625 +/- 0.97025
x = 0.5625 + 0.97025                                   x = 0.5625 - 0.97025
x = 1.53275                                                  x = -0.40775

YFind the slope of the line that passes through the points
(2,-5) and (7.1).
x
2
7
y
-5
1
on
4
Step 1: Choose (X1.71).
2
-4
-2
2
4
ON
8
-2
-4
-6
Check

Answers

Answer:

step 1:

2,-5

step 2:

7,1

step 3:

6/5

Step-by-step explanation:

(1.5 X 10-2) (8.0 X 10-1)

Answers

Answer: 4080

51•80=4080

How do you find the area of a hexagon?

Answers

you break it up into triangles, and from there you multiply 180 by the number of triangles in the hexagon (should be 4 triangles).
you would have to do length times the width or count all the sides.