Disposable gloves are designed for single use and should be discarded after each task to prevent cross-contamination or reduced effectiveness from damage. They should not be reused.
In general, disposable gloves are designed to be used once and then thrown away. They should be removed and discarded after handling a task, then a new pair of gloves should be worn for a different task. This is because reusing disposable gloves can lead to cross-contamination or the gloves becoming less effective if they become damaged from continuous use. For instance, if a person wears the same gloves while treating a patient and then handling medical equipment, bacteria and other harmful substances can spread, creating a risk to health. Therefore, it is crucial to practice accurate and responsible use of disposable gloves in healthcare settings and other scenarios where gloves are required for safety and hygiene purposes.
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To find the efficiency of the system, calculate the input power and output power and then divide the output power by the input power and multiply by 100%.
To find the efficiency of the system consisting of the motor and the lift, we need to calculate the input power and the output power. The input power is given as 1.5 kW. The output power can be calculated by multiplying the weight of the car by the height it was lifted and dividing by the time taken. The efficiency is then calculated by dividing the output power by the input power and multiplying by 100%.
Step 1: Calculate the output power:
Output Power = (Weight of the car) x (Height lifted) / (Time taken)
Step 2: Calculate the efficiency:
Efficiency = (Output Power / Input Power) x 100%
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The efficiency of the hydraulic lift system is found to be 63.7% by comparing the useful power output of lifting the car with the electrical energy input of the motor.
To calculate the efficiency of the system consisting of the motor and the hydraulic lift, we need to compare the useful work output to the energy input. The work done in lifting the car is equal to the product of the gravitational force (weight of the car) and the height raised. With a 1300 kg car, this is 1300 kg × 9.8 m/s2 × 1.8 m. This comes out to 22,932 joules (since work is measured in joules). The time taken is 24 seconds.
Since power is the rate at which work is done or energy is transferred, the useful power output is the work done divided by the time, which is 22,932 joules / 24 seconds = 955.5 watts or 0.9555 kW. Meanwhile, the motor uses electrical energy at a rate of 1.5 kW. To find the efficiency, we divide the useful power by the power input and multiply by 100 to get a percentage:
Efficiency = (0.9555 kW / 1.5 kW) × 100 = 63.7%
Therefore, the efficiency of the motor and the hydraulic lift system is 63.7%.
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93,000
930,000
9,300,00
Answer:
930,000
Explanation:
9.3 x 10^5
The power of 10 (5 in this question) gives the number of times the decimal point is to be moved to the right.
If there was a negative sign in front of the power, the number would have been an indication of how many times the decimal point is to be moved to the left.
Further to this
9.3 x 10^5 = 9.30000000 x 10^5
= 930000.000
= 930,000
Answer:
Cold
Explanation:
It was correct on my quiz
The displacement of a cyclist who travels 1 mile north 1 mile east then finally 1 mile south will be 1 mile in the east direction.
A displacement is a vector in engineering and mechanics that has a length equal to the shortest route between a point P's initial and final positions.
The displacement is the vector quantity that depends on the magnitude as well as direction. And follows the law of vector addition.
The cyclist who travels 1 mile north 1 mile east then finally 1 mile south. Then the diagram is drawn below.
From the graph, the displacement is given as,
Displacement = 1 - 0
Displacement = 1 mile
The displacement of a cyclist who travels 1 mile north 1 mile east then finally 1 mile south will be 1 mile in the east direction.
Learn more about displacement:
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A = B
A< B
It will not slow down, but continue moving at constant velocity.
Answer:
Explanation:
A work pulls the crate by horizontal force on it
Now due to this applied force crate is moving horizontally with uniform speed
so we can say that the acceleration of the crate will be zero
now by Newton's II law we can say
so here we will have
here we know that applied force is A
so F = A
and friction force is B
so correct relation is