Why voltmeter and resistence are parallel in ohm's law.

Answers

Answer 1
Answer: Never mind Ohm's Law.  A voltmeter measures the difference in electrical potential
between two points.  So if you want to measure the difference in electrical potential
between two points, you touch one probe of the meter to each point, and somehow
the internal guts of the meter are able to sense the difference in electrical potential
between the two points.

If the two points have non-reactive impedance (a resistance) between them, then the
difference in electrical potential between the two points, as indicated by the meter,
will be close to (resistance between the two points) x (current flowing between them).



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Whatare two diffent units that represent work

Answers

W=Pt
This means:
Work in Joules (J) = Power in Watts (W) × Time in Seconds (s)

W=Fd
This means:
Work in Joules (J) = Force in Newtons (N) × Distance in Meters (m)

two units for work :
  ~ first is Joule which is equal to Newton .meter ..
  ~ second is kilogram .meter square per second square i.e kgm
²/s²
the second unit is derived from the first unit  Newton .meter 
Newton = kgm/s
² and then multiply m .. it will be equal to kgm²/s²..

Which of these units results when a distance of 35 m is multiplied by a force of 27 n, and then divided by a time of 5s? a newtom n is kg * m/s2 in si base units?

Answers

Answer:

SI unit for Joule per second is (kg m^(2) )/(s^(2) ).

Explanation:

When a distance of 35 m is multiplied by a force of 27 N.

Force × distance = 27 N × 35 m = 945 Joule

945 Joule = 945 (kg m)/(s^(2) ) * m

945 joule = 945 (kg m^(2) )/(s^(2) )

This is SI unit for force multiplied by distance.

The above quantity is divided by 5 s.

(945)/(5) (Joule)/(s) = 189 (kg m^(2) )/(s^(3) )

SI unit for Joule per second is (kg m^(2) )/(s^(2) ).

Answer:

(F * d)/(t) = 189 (kg m^2)/(s^3)

Explanation:

Here first we multiplied the force with the distance so we have

F = 27 N

distance = 35 m

so the product is given as

F* d = 27 N * 35 m

F* d = 945 N m

now we have to divide it by time

so we have

(F * d)/(t) = (945)/(5)

(F * d)/(t) = 189 Nm/s

so it is

(F * d)/(t) = 189 (kg m^2)/(s^3)

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

Answers

Answer:

(Ie)/(lm) = 1.10*10^(-3)

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

(Ie)/(lm) = (-N)/((nf-ni))

(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))

(Ie)/(lm) = 1.10*10^(-3)

Answer:1.105* 10^(-3)

Explanation:

Given

Initial angular speed of engine(\omega _E)=8325 rpm

Final angular speed of engine(\omega _E_f)=12125 rpm

Initial angular speed of Motorcycle(\omega _M)=0 rpm

Final angular speed of engine(\omega _M_f)=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f

I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f

I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f

(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)

(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)

How does a shorter wavelength affect the frequency of a wave?

Answers

The product of (wavelength) x (frequency) is always the same number ... the speed of the wave. So if one of them decreases, the other one must increase in order to keep the product the same. Shorter wavelength means higher frequency. 

Describe and explain how the movement and arrangement of the particles in a block of ice change as the ice melts to form liquid water. In your answer, include ideas about energy transfer.

Answers

Answer:

Ice is water in solid phase, in this phase, the particles are very close together and relatively in fixed positions.

As the temperature starts to increase (thermal energy), also does the kinetic energy of the particles (so we have a change from thermal energy to kinetic energy), so they start to move "more", and the position of the particles starts to be less "fixed". There is a point where the particles have enough energy, and this point is where the phase of the water changes from solid to liquid phase (the fusion point). After this point the water can not hold his shape, and takes the shape of the container where it is.

What is the acceleration of a car moving along a straight road that increases its speed from 0 to 100 km/h in 10 s? 10 m/s2 100 km/h·s 1 km/h·s 10 km/h·s

Answers

100 - 0 km/ 10 seconds. Divide it and then you will get your answer. Answer : 10km/ seconds