Answer:
there are 18.65 grams of sodium nitrate dissolved in 126 grams of the solution that is 14.8% by mass of the compound.
Explanation:
To find the mass of sodium nitrate dissolved in the solution, we can use the concept of percent composition.
First, we need to determine the mass of the solution that is made up of sodium nitrate. Since the solution is 14.8% by mass of the compound, we can calculate this by multiplying the total mass of the solution by the percentage:
Mass of sodium nitrate in solution = (14.8/100) * 126 g
Mass of sodium nitrate in solution = 18.65 g
Therefore, there are 18.65 grams of sodium nitrate dissolved in 126 grams of the solution that is 14.8% by mass of the compound.
B. Higher
Lower Temperature
The boiling point is defined as the temperature at which the vapor pressure of a given liquid becomes equal to the external pressure or atmospheric pressure. Boiling point is mainly effected by following factors:
1) Inter-Molecular Interactions:
Greater the intermolecular interactions greater will be the boiling point because more energy is required to overcome these intermolecular interactions.
Example:
Water = 100 °C
Diethyl ether = 34.5 °C
Water requires more energy because it contains hydrogen bond interactions which are considered the strongest intermolecular interactions. While, Diethyl ether lacks Hydrogen bondings.
2) External Pressure:
The boiling point also varies with changing the external pressure for the same solvent. Greater the external pressure greater will be the boiling points and vice versa.
Example:
Water:
External Pressure Boiling Point
1 atm 100 °C
0.921 atm 98 °C
0.425 atm 72 °C
The number of moles in 987 grams of Ra(OH)2 = 3.8 moles
Ra = 226g
O= 16g
H = 1
Therefore molar mass of Ra(OH)2= 226+ (16+1)×2
= 260g/mol
The molar mass of Ra(OH)2 = 260g/mol
Thus means that 260g of Ra(OH)2 makes up 1 mole
Therefore, 987 g = X moles
Make X moles the subject of formula,
X mole = 987/260
= 3.8 moles
Therefore, the number of moles in 987 grams of Ra(OH)2 = 3.8 moles
Learn more about molar mass here:
Answer : 3.79 moles are in 987 grams of .
Solution : Given,
Mass of = 987 g
Molar mass of = 260 g/mole
Now we have to calculate the moles of .
Formula used :
Now put all the given values in this formula, we get the moles.
Therefore, 3.79 moles are in 987 grams of .
Answer:
I would go for number 5 . It sounds more logical to me.
150 J
B.
270 J
C.
1350 J
D.
2250 J
The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.
W = Fd
W = (450N) (3m)
W = 1350J
The answer is letter C.
Answer:
no tengo la menor idea de que es
What is the color of methyl orange after it is added to this sample?